# tough binomial function question!! help!!

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#1
There's the question.
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#2

part 2 pls
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1 month ago
#3
(Original post by bored_user:))

part 2 pls
The binomial coeffs are an expansion of
(1+x)^n
When x=1
Last edited by mqb2766; 1 month ago
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#4
(Original post by mqb2766)
The binomial covers are an expansion of
(1+x)^n
When x=1
So do I write (1+x)^n = 2^n

and then sent x=1?
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1 month ago
#5
(Original post by bored_user:))
So do I write (1+x)^n = 2^n

and then sent x=1?
No.

Firstly, can you represent as a sum of increasing powers of using the binomial theorem?

Then substitute into both sides of this relation.

Result falls out.
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1 month ago
#6
Expand (1+x)^n
Then set x=1 in both the expansion and the original expression.
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#7
(Original post by RDKGames)
No.

Firstly, can you represent as a sum of increasing powers of using the binomial theorem?

Then substitute into both sides of this relation.

Result falls out.

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#8
(Original post by mqb2766)
Expand (1+x)^n
Then set x=1 in both the expansion and the original expression.
How do I even expand that when n has no value??
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1 month ago
#9
(Original post by bored_user:))

Are you actually setting x=1 in the expansion of the binomial?
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1 month ago
#10
(Original post by bored_user:))
Almost.

Is really the series expansion of ?
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1 month ago
#11
(Original post by mqb2766)
Are you actually setting x=1 in the expansion of the binomial?
(1+x)^n = 1+nx + n(n-1)/2x^2 + ... + x^n
When x=1, the right equals ?
Last edited by mqb2766; 1 month ago
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#12
(Original post by RDKGames)
Almost.

Is really the series expansion of ?
I have no idea what's going on here...

Can you tell me what the correct answer is and explain it please? Thanks
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1 month ago
#13
TBH, you should've come across the binomial theorem (which is also in the Edexcel formula booklet!) when it tells you that

Choosing appropriate values for makes the answer fall out immediately.
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1 month ago
#14
(Original post by bored_user:))
I have no idea what's going on here...

Can you tell me what the correct answer is and explain it please? Thanks
What is the binomial expansion of
(1+x)^n
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#15
(Original post by mqb2766)
(1+x)^n = 1+nx + n(n-1)/2x^2 + ... + x^n
When x=1, the right equals ?
is this it?
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1 month ago
#16
(Original post by bored_user:))
is this it?
Yes. The rows in Pascal triangle sum to 2^n.
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#17
(Original post by mqb2766)
Yes
Omg thank you so much for helping!!!
1
1 month ago
#18
Yep, super tough.

Rufus the red
nikkiblonsky
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#19
(Original post by jellybellyb)
Yep, super tough.

Rufus the red
nikkiblonsky
This is uni stuff lol.
0
1 month ago
#20
(Original post by jellybellyb)
Yep, super tough.

Rufus the red
nikkiblonsky
1
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