deviany
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i dont understand part 2
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RDKGames
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(Original post by deviany)
i dont understand part 2
Given the graph of f(x) I hope you know how |f(x)| looks like.

That being said, notice that for |f(x)| in this case each of the 'humps' will have area of A.

In part (i) you found that A = \displaystyle \int_0^{\pi/4} |f(x)| \ dx

Note that the the area of the first two humps is then

2A = \displaystyle \int_0^{2\cdot \pi/4} |f(x)| \ dx

Can you work out the question from there?
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deviany
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(Original post by RDKGames)
Given the graph of f(x) I hope you know how |f(x)| looks like.

That being said, notice that for |f(x)| in this case each of the 'humps' will have area of A.

In part (i) you found that A = \displaystyle \int_0^{\pi/4} |f(x)| \ dx

Note that the the area of the first two humps is then

2A = \displaystyle \int_0^{2\cdot \pi/4} |f(x)| \ dx

Can you work out the question from there?
just to make sure if i get the correct understanding. so if 2A is pi/2 and A is pi/4... and i want to know the interval when there is 40 humps so pi/4×40 =10pi. therefore k is 10. is that right?
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RDKGames
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(Original post by deviany)
just to make sure if i get the correct understanding. so if 2A is pi/2 and A is pi/4... and i want to know the interval when there is 40 humps so pi/4×40 =10pi. therefore k is 10. is that right?
Yes.
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