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#1
Can anyone help with any of these questions?

Attachment 968608

Attachment 968610
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4 weeks ago
#2
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#3
(Original post by mqb2766)

Is this better ?
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4 weeks ago
#4
(Original post by thisQUEENslayz)

Is this better ?
Which are you having trouble with / what have you tried?
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#5
So far I’ve managed to do 1,2 and 3
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#6
(Original post by mqb2766)
Which are you having trouble with / what have you tried?
I’ve done 1,2 and 3 so far
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4 weeks ago
#7
(Original post by thisQUEENslayz)
I’ve done 1,2 and 3 so far
4 is a little blurry, but you know the area and perimeter and the length in terms of x.
use the perimeter to get the width in terms of x, then multiply to equate to the area?

Then transform the hidden/ disguised quadratic and solve.
Last edited by mqb2766; 4 weeks ago
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#8
(Original post by mqb2766)
4 is a little blurry, but you know the area and perimeter and the length in terms of x.
use the perimeter to get the width in terms of x, then multiply to equate to the area?

Then transform the hidden/ disguised quadratic and solve.
I’m still a bit confused with the width
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4 weeks ago
#9
(Original post by thisQUEENslayz)
I’m still a bit confused with the width
You know the rectangle perimeter and the length (in terms of x). So the width, as a function of x, should be easy?

Length+width = perimeter/2
Last edited by mqb2766; 4 weeks ago
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