# probability distrubtion question

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#1
question 8a
im confused as to how they got the values for 3 and 4??

the answers for the proabilites are 1- 0.28, 2-0.21, 3-0.28, 4-0.21
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4 weeks ago
#2
haha bumping this bc I would like to know how you get that too
0
4 weeks ago
#3
(Original post by vix.xvi)
question 8a
im confused as to how they got the values for 3 and 4??

the answers for the proabilites are 1- 0.28, 2-0.21, 3-0.28, 4-0.21

From the given relationship, P(X=1) = P(X=4)= 0.28

Can you work out P(X=2), P(X=3) now?
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#4
(Original post by ghostwalker)

From the given relationship, P(X=1) = P(X=4)= 0.28

Can you work out P(X=2), P(X=3) now?
wait sorry how did you know that P(X=1) = P(X=4)?
(Original post by laurawatt)
haha bumping this bc I would like to know how you get that too
0
4 weeks ago
#5
(Original post by vix.xvi)
wait sorry how did you know that P(X=1) = P(X=4)?
The third line of the question tells you - when setting r to 1.
1
#6
(Original post by ghostwalker)
The third line of the question tells you - when setting r to 1.
ohhhhh

so p(x=2) and p(x=3) is 0.22????

wait so r the answers wrong then?
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4 weeks ago
#7
(Original post by vix.xvi)
ohhhhh

so p(x=2) and p(x=3) is 0.22????
Agreed.

wait so r the answers wrong then?
Yes, the given answers are incorrect.
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#8
(Original post by ghostwalker)
Agreed.

Yes, the given answers are incorrect.
thanks for ur help!

(Original post by laurawatt)
haha bumping this bc I would like to know how you get that too
tagging u cuz u wanted to know too aha
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4 weeks ago
#9
(Original post by vix.xvi)
thanks for ur help!

tagging u cuz u wanted to know too aha
haha thank you! makes a lot more sense!
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