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For the Arrhenius equation, when you are plotting graphs for the rate constant (k) against temperature (K), why do you do temperature as 1/T?
Thanks in advance!
Thanks in advance!
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#2
To plot the graph, you use the log form of the Arrhenius equation:
log k = -Ea/RT + ln A
This is in the form of a graph, y = mx +c. If you compare the two equations, you can see that:
y = log k
m = -Ea/R
x = 1/T
c = ln A
So when you're plotting a graph of y against x, you plot log k against 1/T
You wouldn't use Ea or R as x because they're both constants, and it's not a graph if x is constant (or at least, not a graph that tells you anything)
Let me know if that helps
log k = -Ea/RT + ln A
This is in the form of a graph, y = mx +c. If you compare the two equations, you can see that:
y = log k
m = -Ea/R
x = 1/T
c = ln A
So when you're plotting a graph of y against x, you plot log k against 1/T
You wouldn't use Ea or R as x because they're both constants, and it's not a graph if x is constant (or at least, not a graph that tells you anything)
Let me know if that helps
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(Original post by Ensorcell)
To plot the graph, you use the log form of the Arrhenius equation:
log k = -Ea/RT + ln A
This is in the form of a graph, y = mx +c. If you compare the two equations, you can see that:
y = log k
m = -Ea/R
x = 1/T
c = ln A
So when you're plotting a graph of y against x, you plot log k against 1/T
You wouldn't use Ea or R as x because they're both constants, and it's not a graph if x is constant (or at least, not a graph that tells you anything)
Let me know if that helps
To plot the graph, you use the log form of the Arrhenius equation:
log k = -Ea/RT + ln A
This is in the form of a graph, y = mx +c. If you compare the two equations, you can see that:
y = log k
m = -Ea/R
x = 1/T
c = ln A
So when you're plotting a graph of y against x, you plot log k against 1/T
You wouldn't use Ea or R as x because they're both constants, and it's not a graph if x is constant (or at least, not a graph that tells you anything)
Let me know if that helps
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#4
I would use a scale of K x10^-3 (K being Kelvin)
That way you can plot as if you were using normal numbers!!
Best of luck
That way you can plot as if you were using normal numbers!!
Best of luck
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