TSR George
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For the Arrhenius equation, when you are plotting graphs for the rate constant (k) against temperature (K), why do you do temperature as 1/T?

Thanks in advance!
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Ensorcell
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To plot the graph, you use the log form of the Arrhenius equation:

log k = -Ea/RT + ln A

This is in the form of a graph, y = mx +c. If you compare the two equations, you can see that:
y = log k
m = -Ea/R
x = 1/T
c = ln A

So when you're plotting a graph of y against x, you plot log k against 1/T


You wouldn't use Ea or R as x because they're both constants, and it's not a graph if x is constant (or at least, not a graph that tells you anything)


Let me know if that helps
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TSR George
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(Original post by Ensorcell)
To plot the graph, you use the log form of the Arrhenius equation:

log k = -Ea/RT + ln A

This is in the form of a graph, y = mx +c. If you compare the two equations, you can see that:
y = log k
m = -Ea/R
x = 1/T
c = ln A

So when you're plotting a graph of y against x, you plot log k against 1/T


You wouldn't use Ea or R as x because they're both constants, and it's not a graph if x is constant (or at least, not a graph that tells you anything)


Let me know if that helps
thanks! Also on the topic of graphs with regards to the Arrhenius equation, say if the temperature is 556K, the 1/T value would be1.80x10^-3. How would you plot these types of numbers for 1/T on the x axis? (like what scale would you use)
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Ensorcell
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I would use a scale of K x10^-3 (K being Kelvin)
That way you can plot as if you were using normal numbers!!
Best of luck
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