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#1
The radius of a nucleus of the iron nuclide is 4.35 × 10–15 m.

What is the radius of a nucleus of the uranium nuclide ?

A

2.69 × 10–15 m

B

2.89 × 10–15 m

C

6.55 × 10–15 m

D

7.05 × 10–15 m

(Total 1 mark)

How would I even do this? It isn't on the spec
1
2 months ago
#2
Nuclear density is constant

density = mass/volume
mass = density x volume
density constant so mass proportional to volume
hence ratio of mass number = ratio of volume
but volume is proportional to nuclear radius^3
so ratio of mass number = (ratio of nuclear radius)^3

i.e mass of uranium nuclide / mass of iron nuclide = (nuclear radius of uranium nuclide / nuclear radius of iron nuclide)^3

hence replace and solve for the unknown
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