# Electrical

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Thread starter 2 months ago
#1
hi does anyone know how do i draw a circuit that will convert a galvanometer with a full-scale deflection (f.s.d.) of 1mA and internal resistance of 20Ω into an instrument capable ofmeasuring up to 1A.and another circuit to convert the same galvanometer to read 10 volts f.s.d.
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2 months ago
#2
(Original post by sona125)
hi does anyone know how do i draw a circuit that will convert a galvanometer with a full-scale deflection (f.s.d.) of 1mA and internal resistance of 20Ω into an instrument capable ofmeasuring up to 1A.and another circuit to convert the same galvanometer to read 10 volts f.s.d.
The technical term you need to look up to get you started is "current shunt". You are also going to need to be able to calculate current and voltage in series and parallel resistor circuits.
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1 month ago
#3
(Original post by sona125)
hi does anyone know how do i draw a circuit that will convert a galvanometer with a full-scale deflection (f.s.d.) of 1mA and internal resistance of 20Ω into an instrument capable ofmeasuring up to 1A.and another circuit to convert the same galvanometer to read 10 volts f.s.d.
For the first, place a resistor in parallel with the meter, so that only 1mA flows through it when a total of 1A flows, i.e. 999mA goes through the parallel resistor.

For the second, place a resistor in series, so that a voltage of 10V drives a current if 1mA.
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