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The Chameleon
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#1
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#1
Find the value(s) of x that satisfy the following equation.

4(2^(2x)) = 16^x
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El Stevo
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#2
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4(2^(2x)) = 16^x
2.2.2^(2x)=2.2.2.2^(x)
2^(2x+2)=2^(x+3)
2x+2=x+3
x=1
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nas7232
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#3
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Just checking via my method

4(2^(2x)) = 16^x
cancel down by dividing by 4
(2^(2x)) = 4^x

(2^(2x)) = (2^2)^x
let y = 2^2
therefore:
y^1 = y ^x
1=x
x=1
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john !!
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(Original post by The Chameleon)
Find the value(s) of x that satisfy the following equation.

4(2^(2x)) = 16^x
(2^2)(2^(2x)) = 2^4x
2^(2+2x) = 2^4x
2 + 2x = 4x
2 = 2x
x = 1
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Christophicus
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#5
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#5
x = 1
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NikolaiJ
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#6
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#6
(Original post by Widowmaker)
x = 1
lmao... sweet
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Christophicus
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#7
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#7
(Original post by NikolaiJ)
lmao... sweet
here's my working.

http://www.thestudentroom.co.uk/show...97#post1488397
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