# C1 questionWatch

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#1
Find the value(s) of x that satisfy the following equation.

4(2^(2x)) = 16^x
0
14 years ago
#2
4(2^(2x)) = 16^x
2.2.2^(2x)=2.2.2.2^(x)
2^(2x+2)=2^(x+3)
2x+2=x+3
x=1
0
14 years ago
#3
Just checking via my method

4(2^(2x)) = 16^x
cancel down by dividing by 4
(2^(2x)) = 4^x

(2^(2x)) = (2^2)^x
let y = 2^2
therefore:
y^1 = y ^x
1=x
x=1
0
14 years ago
#4
(Original post by The Chameleon)
Find the value(s) of x that satisfy the following equation.

4(2^(2x)) = 16^x
(2^2)(2^(2x)) = 2^4x
2^(2+2x) = 2^4x
2 + 2x = 4x
2 = 2x
x = 1
0
14 years ago
#5
x = 1
0
14 years ago
#6
(Original post by Widowmaker)
x = 1
lmao... sweet
0
14 years ago
#7
(Original post by NikolaiJ)
lmao... sweet
here's my working.

http://www.thestudentroom.co.uk/show...97#post1488397
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