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Yazomi
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#1
I can’t seem to get to a=4? I got 7.21=a instead. Can someone explain why/how to get to 4=a plsss
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mqb2766
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#2
The resultant force is nonzero in the y direction so you can't balance the forces in a triangle.
Resolve the forces in x and y directions. What must happen in the x direction?
Resolve the forces in x and y directions. What must happen in the x direction?
Last edited by mqb2766; 1 year ago
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Yazomi
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#3
(Original post by mqb2766)
The resultant force is nonzero in the y direction so you can't balance the forces in a triangle.
Resolve the forces in x and y directions. What must happen in the x direction?
The resultant force is nonzero in the y direction so you can't balance the forces in a triangle.
Resolve the forces in x and y directions. What must happen in the x direction?
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#4
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#4
(Original post by Yazomi)
Be equal to 6n?
Be equal to 6n?
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Yazomi
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#5
(Original post by mqb2766)
Sort of. The net force in the x direction should be 0.
Sort of. The net force in the x direction should be 0.
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#6
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#6
(Original post by Yazomi)
But I’m confused as to why that should be 0 if it’s not in equilibrium and that the y direction shouldn’t be equal?
But I’m confused as to why that should be 0 if it’s not in equilibrium and that the y direction shouldn’t be equal?
So it can be in equilibrium in the x direction, but have a non-stop resultant force (not in equilibrium) in the y direction.
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Yazomi
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#7
(Original post by mqb2766)
Forces in orthogonal directions (90 degrees to each other) are independent.
So it can be in equilibrium in the x direction, but have a non-stop resultant force (not in equilibrium) in the y direction.
Forces in orthogonal directions (90 degrees to each other) are independent.
So it can be in equilibrium in the x direction, but have a non-stop resultant force (not in equilibrium) in the y direction.
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#8
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#8
(Original post by Yazomi)
So to have a resultant force, the equilibrium isn’t equal? And if x is (for instance) is not in equilibrium do I automatically assume that y would be in equilibrium?
So to have a resultant force, the equilibrium isn’t equal? And if x is (for instance) is not in equilibrium do I automatically assume that y would be in equilibrium?
* The resultant force in the x direction is zero.
* The resultant force in the y direction is non-zero
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Yazomi
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#9
(Original post by mqb2766)
The question tells you that the resultant force is in the y direction, so
* The resultant force in the x direction is zero.
* The resultant force in the y direction is non-zero
The question tells you that the resultant force is in the y direction, so
* The resultant force in the x direction is zero.
* The resultant force in the y direction is non-zero
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#10
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#10
(Original post by Yazomi)
Ahhhhhh trying to get me head around mechanics, I got you now tho thanks!! Finally made sense
Ahhhhhh trying to get me head around mechanics, I got you now tho thanks!! Finally made sense
https://www.youtube.com/watch?v=fm5C4FvI6Po&app=desktop
The vertical (ball) motion does not affect the horizontal (ball) speed.
Last edited by mqb2766; 1 year ago
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Yazomi
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#11
(Original post by mqb2766)
Spot the independent ball motion towards the end
https://www.youtube.com/watch?v=fm5C4FvI6Po&app=desktop
The vertical (ball) motion does not affect the horizontal (ball) speed.
Spot the independent ball motion towards the end
https://www.youtube.com/watch?v=fm5C4FvI6Po&app=desktop
The vertical (ball) motion does not affect the horizontal (ball) speed.
If it’s large scale enough friction would affect it wouldn’t it
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#12
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#12
(Original post by Yazomi)
It would be the horizontal direction wouldn’t it,
If it’s large scale enough friction would affect it wouldn’t it
It would be the horizontal direction wouldn’t it,
If it’s large scale enough friction would affect it wouldn’t it
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