Gibbs Free EnergyWatch
But the equation for Gibb's free energy does not consider kinetic stability of a system. This means that the value for Gibb's free energy can fall below zero, thus be thermodynamically 'feasible' even if the activation energy for the reaction is not met. In this case, the reaction wouldn't proceed / be infinitesimally slow (as activation energy has not been met by all reactant particles), even though the system's thermodynamics are all good to go (i.e. the reaction is technically 'feasible'), no?