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Please help with this question: A particle is projected at a speed of 12ms-1 up a straight inclined track. Whilst on the track the particle experiences a constant acceleration down the track of 5ms-2. Find the length of time that the particle is more than 8 metres from the point of projection.
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#2
not sure how to do the whole question but to start use the SUVAT equations ->
s = 8
u = 12
v = v
a = 5
t = ?
s = 8
u = 12
v = v
a = 5
t = ?
Last edited by milliebaudot; 1 month ago
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#3
(Original post by Risermax)
Please help with this question: A particle is projected at a speed of 12ms-1 up a straight inclined track. Whilst on the track the particle experiences a constant acceleration down the track of 5ms-2. Find the length of time that the particle is more than 8 metres from the point of projection.
Please help with this question: A particle is projected at a speed of 12ms-1 up a straight inclined track. Whilst on the track the particle experiences a constant acceleration down the track of 5ms-2. Find the length of time that the particle is more than 8 metres from the point of projection.
(I have one but not sure it’s right)
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#5
(Original post by Risermax)
No I do not
No I do not
What have you done so far?
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#6
(Original post by milliebaudot)
not sure if this helps as I'm not sure how to do the whole question but to start use the SUVAT equations ->
s = 8
u = 12
v = v
a = 5
t = ?
not sure if this helps as I'm not sure how to do the whole question but to start use the SUVAT equations ->
s = 8
u = 12
v = v
a = 5
t = ?
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(Original post by GabiAbi84)
Ah, shoot. I like to know I’m right before I help..
What have you done so far?
Ah, shoot. I like to know I’m right before I help..
What have you done so far?
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(Original post by Risermax)
I just wrote the suvat for it but Im still not sure whether gravity has anything to do with it so is a: 5 or 9.81
I just wrote the suvat for it but Im still not sure whether gravity has anything to do with it so is a: 5 or 9.81
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#9
(Original post by Risermax)
I just wrote the suvat for it but Im still not sure whether gravity has anything to do with it so is a: 5 or 9.81
I just wrote the suvat for it but Im still not sure whether gravity has anything to do with it so is a: 5 or 9.81
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(Original post by GabiAbi84)
It is on a track and the question tells you the constant acceleration is 5m/s DOWN the track.
It is on a track and the question tells you the constant acceleration is 5m/s DOWN the track.
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#11
(Original post by Risermax)
So did you get 0.44 (3sf) as your final answer
So did you get 0.44 (3sf) as your final answer
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(Original post by GabiAbi84)
I did not...but that doesn’t mean you’re not correct. Show your working
I did not...but that doesn’t mean you’re not correct. Show your working
Subbed in the values to get
8 = 12t+2.5t^2
Then did 2.5t^2+12t-8 = 0
Did the quadratic formula and got 0.5933...
So not 0.44 my bad
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#13
(Original post by Risermax)
I did s = ut+1/2at^2
Subbed in the values to get
8 = 12t+2.5t^2
Then did 2.5t^2+12t-8 = 0
Did the quadratic formula and got 0.5933...
So not 0.44 my bad
I did s = ut+1/2at^2
Subbed in the values to get
8 = 12t+2.5t^2
Then did 2.5t^2+12t-8 = 0
Did the quadratic formula and got 0.5933...
So not 0.44 my bad
Also your acceleration is down the track so should be negative.
(My confusion lies in whether it returns back to the start once it gets to the top point of the track)
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#14
(Original post by GabiAbi84)
You’re looking for the length of time it is More than 8 metres away.
Also your acceleration is down the track so should be negative.
(My confusion lies in whether it returns back to the start once it gets to the top point of the track)
You’re looking for the length of time it is More than 8 metres away.
Also your acceleration is down the track so should be negative.
(My confusion lies in whether it returns back to the start once it gets to the top point of the track)
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(Original post by GabiAbi84)
You’re looking for the length of time it is More than 8 metres away.
Also your acceleration is down the track so should be negative.
(My confusion lies in whether it returns back to the start once it gets to the top point of the track)
You’re looking for the length of time it is More than 8 metres away.
Also your acceleration is down the track so should be negative.
(My confusion lies in whether it returns back to the start once it gets to the top point of the track)
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#17
(Original post by Risermax)
I don't think it does, but how did you work it out?
I don't think it does, but how did you work it out?
Last edited by GabiAbi84; 1 month ago
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(Original post by GabiAbi84)
I started by working out the time until it stops moving upwards.
I started by working out the time until it stops moving upwards.
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