# Mechanics- velocity and acceleration

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#1
Its question 11
Last edited by Shas72; 1 month ago
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1 month ago
#2
(Original post by Shas72)
Its question 11
What does that diagram show?
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#3
it shows decelerating
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1 month ago
#4
(Original post by Shas72)
it shows decelerating
Is that what you understand is happening to the velocity, as described in the question?
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#5
the block is lifted from ground at a constant speed till 5s. after 5s it slips and decelerates at 10m/s^2 and reaches a height of 6m which means the total area under the graph is 6m
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1 month ago
#6
(Original post by Shas72)
the block is lifted from ground at a constant speed till 5s. after 5s it slips and decelerates at 10m/s^2 and reaches a height of 6m which means the total area under the graph is 6m
That's what the question says, does your graph show that?
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#7
(Original post by mqb2766)
That's what the question says, does your graph show that?
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1 month ago
#8
(Original post by Shas72)
Have a think for maybe 10 minutes and explicitly match the different sections to the question. There are a few important mistakes even though the graph is relatively simple. The more you can do yourself, the better you'll understand/remember. If you have a specific question about what something means, post that.
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#9
(Original post by mqb2766)
Have a think for maybe 10 minutes and explicitly match the different sections to the question. There are a few important mistakes even though the graph is relatively simple. The more you can do yourself, the better you'll understand/remember. If you have a specific question about what something means, post
Can you pls tell me if my second graph is right?
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1 month ago
#10
There are a few important mistakes even though the graph is relatively simple
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#11
(Original post by mqb2766)
There are a few important mistakes even though the graph is relatively simple
Ok thanks! Let me try
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#12
(Original post by mqb2766)
There are a few important mistakes even though the graph is relatively simple
Can you pls sketch the graph if its not inconvenient or can you pls give me a hint on how to solve this question. I have tried to do in diff ways of using a = v-u/t
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#13
(Original post by mqb2766)
Have a think for maybe 10 minutes and explicitly match the different sections to the question. There are a few important mistakes even though the graph is relatively simple. The more you can do yourself, the better you'll understand/remember. If you have a specific question about what something means, post that.
Also if its ground level u is 0. So when I do a = v-u/t, I get -50
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#14
(Original post by mqb2766)
There are a few important mistakes even though the graph is relatively simple
Thanks! I got the ans. I came to know where I was doing mistakes
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#15
(Original post by mqb2766)
There are a few important mistakes even though the graph is relatively simple
And it was very very simple. I was unnecessarily complicating it
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#16
(Original post by mqb2766)
Have a think for maybe 10 minutes and explicitly match the different sections to the question. There are a few important mistakes even though the graph is relatively simple. The more you can do yourself, the better you'll understand/remember. If you have a specific question about what something means, post th
Attachment 977412 I got the ans but without the graph and mainly using the displacement and not the concept of area under the graph. I still don't get the ans with the graph. Can you pls guide
Last edited by Shas72; 1 month ago
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#17
(Original post by mqb2766)
Have a think for maybe 10 minutes and explicitly match the different sections to the question. There are a few important mistakes even though the graph is relatively simple. The more you can do yourself, the better you'll understand/remember. If you have a specific question about what something means, post that.
I got the ans using displacement and not the area under the graph. Can you pls tell me where am I going wrong in the graph part
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1 month ago
#18
(Original post by Shas72)
I got the ans using displacement and not the area under the graph. Can you pls tell me where am I going wrong in the graph part
Sure, can you upload your current attempt at the velocity-time graph? Maybe (briefly) mark on each section why you think it's that shape. I don't care whether the graph is right. I do care whether you try to explain your thinking behind the graph.
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#19
(Original post by mqb2766)
Sure, can you upload your current attempt at the velocity-time graph? Maybe (briefly) mark on each section why you think it's that shape. I don't care whether the graph is right. I do care whether you try to explain your thinking behind the graph.
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1 month ago
#20
(Original post by Shas72)
Your constant speed label is correct, but what does your graph section show?
What is the speed when t=1,2,3,4,5? Is it constant?
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