# Mechanics- velocity and acceleration

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I have solved it but I want to know how to solve it just by taking velocity values. I calculated displacement and then subtracted s2-s1 to get 6.25m.

Since iam doing the topic which focuses on area under the graph can someone help me how to calculate without calculating displacement

Since iam doing the topic which focuses on area under the graph can someone help me how to calculate without calculating displacement

Last edited by Shas72; 1 month ago

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#2

(Original post by

I have solved it but I want to know how to solve it just by taking velocity values. I calculated displacement and then subtracted s2-s1 to get 6.25m.

Since iam doing the topic which focuses on area under the graph can someone help me how to calculate without calculating displacement

**Shas72**)I have solved it but I want to know how to solve it just by taking velocity values. I calculated displacement and then subtracted s2-s1 to get 6.25m.

Since iam doing the topic which focuses on area under the graph can someone help me how to calculate without calculating displacement

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(Original post by

Which question?

**mqb2766**)Which question?

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#4

(Original post by

Sorry its the 4th question

**Shas72**)Sorry its the 4th question

How is it related to your calculation and what was your calculation?

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I calculated the displacement and subtracted s2-s1 for both the velocity values

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#7

(Original post by

I calculated the displacement and subtracted s2-s1 for both the velocity values

**Shas72**)I calculated the displacement and subtracted s2-s1 for both the velocity values

(Original post by

area under the graph would be the area of triangle.

**Shas72**)area under the graph would be the area of triangle.

It usually takes ~8 posts to find out what you've done.

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I calculated the two displacement taking both the velocity values. I got the ans. I just want to know if I can calculate directly without calculating displacement.

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#9

(Original post by

I calculated the two displacement taking both the velocity values. I got the ans. I just want to know if I can calculate directly without calculating displacement.

**Shas72**)I calculated the two displacement taking both the velocity values. I got the ans. I just want to know if I can calculate directly without calculating displacement.

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(Original post by

The calculation can be done using the (signed) area ( between the curve and the x-axus).

**mqb2766**)The calculation can be done using the (signed) area ( between the curve and the x-axus).

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**mqb2766**)

The calculation can be done using the (signed) area ( between the curve and the x-axus).

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#12

(Original post by

You mean the area that I have marked with the pencil?

**Shas72**)You mean the area that I have marked with the pencil?

Last edited by mqb2766; 1 month ago

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#13

(Original post by

Also wanted to know whether its ok to calculate using displacement as I find it easier in some cases of velocity time graph

**Shas72**)Also wanted to know whether its ok to calculate using displacement as I find it easier in some cases of velocity time graph

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(Original post by

No, that's not how you integrate, but Its hard to see which area you're talking about.

**mqb2766**)No, that's not how you integrate, but Its hard to see which area you're talking about.

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#16

(Original post by

is it the area of the triangle between the points 1 and 1.5

**Shas72**)is it the area of the triangle between the points 1 and 1.5

**signed area**for the graph.

Do you know what that is?

Last edited by DFranklin; 1 month ago

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#19

(Original post by

is it the whole triangle with points 10, -15

**Shas72**)is it the whole triangle with points 10, -15

(Original post by

yes pls if you can tell me it would be very very helpful

**Shas72**)yes pls if you can tell me it would be very very helpful

Previously, I stopped replying to you because it's so frustrating. and I felt bad about giving you a bad time. But observing recent posts by you, what I see is:

People ask you questions about what you're doing, and you ignore them, or answer something else (basically, what you imagine they asked insead of what they actually asked)..

People tell you to do "X", and you're response makes it clear you've done something completely different.

People tell you to think before you post, and in less than 2 minutes there's another (hopelessly wrong) response from you.

You can't blame this on homeschooling. It seems you simply don't pay attention to the responses people post. (One thing I'll point out: mathematical language is

**precise**, If you don't understand what "X" means, don't guess, because you will very likely be wrong. Either google it, or ask, or if you must guess,

**say**that you're guessing: e.g. "I'm guessing that signed area means the area of the big triangle, in which case ..."

On which note, I'm guessing that you don't know what signed area is, in which case the youtube video with identifier MTCpI2ihdEM might help. (I'm not giving you a link, because I want to see if you actually pay attention to this post as opposed to just clicking on anything clickable).

Last edited by DFranklin; 1 month ago

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so basically I just find the area of triangle = 5×2.5/2. v2-v1=5 and total time is 2.5

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