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Thermo Complete Combustion Question

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Raining in TOKYO
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So i've had a major brain fart and have no clue how to go about this question.

https://ibb.co/J3Vxtkr

Part a) I think that I need to find the stoichiometric coefficient for O2 and then divide that by 21 and multiply by 100 to find the theoretical air.

So I went about making an equation for the complete combustion of the gas and ended up with 53 as the coefficient and therefore 252kmol but this is way off.
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cflau_
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For the combustion equations:

CH_4 + 2O_2 \to CO_2 + 2H_2O

C_2H_4 + 3O_2 \to 2CO_2 + 2H_2O

C_3H_8 + 5O_2 \to 3CO_2 + 4H_2O

\text{Number of moles of methane present in 1kmol of gas }=1000 \times 0.4 = 400

\text{Number of moles of ethene present in 1kmol of gas }=1000 \times 0.24 = 240

\text{Number of moles of propane present in 1kmol of gas }=1000 \times 0.16 = 160

\text{Number of moles of oxygen needed }= 400 \times 2 + 240 \times 3 + 160 \times 5=2320

You can work out the number of kmols of air from here.
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