# physics question

Watch
Announcements
#1
Need help with part D
https://isaacphysics.org/questions/h...9-6aebeb08a305
Last edited by aominedaiki; 1 month ago
0
1 month ago
#2
What have you done?
0
#3
(Original post by Eimmanuel)
What have you done?
I have equated work done equation and kinetic energy equation and am not sure what to do from their.
0
1 month ago
#4
(Original post by aominedaiki)
I have equated work done equation and kinetic energy equation and am not sure what to do from their.
What are you supposed to find?
What are you given?
0
#5
(Original post by Eimmanuel)
What are you supposed to find?
What are you given?
It says in the question if you scroll up it gives you the different information.
0
1 month ago
#6
(Original post by aominedaiki)
It says in the question if you scroll up it gives you the different information.
The questions are for you NOT for me.
If you know what to find, from the conservation of energy equation you should be able to find what you want.
0
#7
(Original post by Eimmanuel)
The questions are for you NOT for me.
If you know what to find, from the conservation of energy equation you should be able to find what you want.
yes ik thats why I equated the work done and kinetic energy equations
0
1 month ago
#8
(Original post by aominedaiki)
yes ik thats why I equated the work done and kinetic energy equations
Then what is your problem that you face in doing the question.
0
#9
(Original post by Eimmanuel)
Then what is your problem that you face in doing the question.
I am unsure on what to do since once I have equated them I have tried to find the force but for some reason after I do that it says I have still got it wrong, it actually says "remember that the hammer and nail remain in contact during and after the blow." I was wondering how that would affect my calculations a lot since I assumed once it reached zero velocity the loss of ke would still be equal to the work done?
0
1 month ago
#10
(Original post by aominedaiki)
I am unsure on what to do since once I have equated them I have tried to find the force but for some reason after I do that it says I have still got it wrong, it actually says "remember that the hammer and nail remain in contact during and after the blow." I was wondering how that would affect my calculations a lot since I assumed once it reached zero velocity the loss of ke would still be equal to the work done?
When the hammer hits the nail, this is an inelastic collision.
(Original post by aominedaiki)
yes ik thats why I equated the work done and kinetic energy equations
It seems that there is some difference(s) in your working and what you have described.
0
#11
(Original post by Eimmanuel)
When the hammer hits the nail, this is an inelastic collision.

It seems that there is some difference(s) in your working and what you have described.
I have got it now thanks for your help
0
X

new posts
Back
to top
Latest
My Feed

### Oops, nobody has postedin the last few hours.

Why not re-start the conversation?

see more

### See more of what you like onThe Student Room

You can personalise what you see on TSR. Tell us a little about yourself to get started.

### Poll

Join the discussion

#### Have you experienced financial difficulties as a student due to Covid-19?

Yes, I have really struggled financially (78)
18.1%
I have experienced some financial difficulties (124)
28.77%
I haven't experienced any financial difficulties and things have stayed the same (162)
37.59%
I have had better financial opportunities as a result of the pandemic (54)
12.53%
3.02%