Mechanics- velocity and acceleration
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Its question 12. Iam not understanding how to solve 12(b)
Attachment 977806
Last edited by Shas72; 1 month ago
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ok I will try. thanks! my question is do I have to take the values till t=12
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#4
(Original post by Shas72)
ok I will try. thanks! my question is do I have to take the values till t=12
ok I will try. thanks! my question is do I have to take the values till t=12
(2) Have you actually read the question carefully? This (plus a little common sense) would tell you "t=12" is not relevant to part (b).
I wouldn't respond like this, if this wasn't what happens pretty much *every* time you post a question. You don't state what your actual problem is, and when you do, it becomes apparent you either haven't read the question properly or (as the thread continues) you haven't read people's suggestions properly.
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I understood how to get the expression 40+20(t-4). I don't understand how is it 22(t-10)-1/2(t-10)^2
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#6
(Original post by Shas72)
I understood how to get the expression 40+20(t-4). I don't understand how is it 22(t-10)-1/2(t-10)^2
I understood how to get the expression 40+20(t-4). I don't understand how is it 22(t-10)-1/2(t-10)^2
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#8
(Original post by Shas72)
yes I have read the question properly
yes I have read the question properly
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pls explain how to calculate the distance of the truck. I don't understand how to find the area under the curve for the truck
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#10
(Original post by Shas72)
pls explain how to calculate the distance of the truck. I don't understand how to find the area under the curve for the truck
pls explain how to calculate the distance of the truck. I don't understand how to find the area under the curve for the truck
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I did that already. I don't understand how to get the expression 22(t-10)-1/2(t-10)^2. if possible pls show me a few steps. I will work on it
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#12
(Original post by Shas72)
~snip~
~snip~
(Original post by DFranklin)
Break the graph into regions you do understand how to find the area for (e.g. rectangles and triangles) and add them up.
Break the graph into regions you do understand how to find the area for (e.g. rectangles and triangles) and add them up.
For the record, I'm had enough - I'm not going to keep wasting my time on someone who doesn't follow instructions, and for whom trying to get information feels like getting blood from a stone.
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ok thanks will try myself. its a bit discouraging when you talk like this. The forum is meant for students who are willing to help others. its absolutely fine if you don't want to.
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#14
(Original post by Shas72)
ok thanks will try myself. its a bit discouraging when you talk like this. The forum is meant for students who are willing to help others. its absolutely fine if you don't want to.
ok thanks will try myself. its a bit discouraging when you talk like this. The forum is meant for students who are willing to help others. its absolutely fine if you don't want to.
They have been giving you help, you just aren’t doing the steps they ask you to do.
The forums are not meant to replace school/tutors by teaching you to topics-they are simply to give a guiding hand.
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#15
(Original post by GabiAbi84)
I don’t think that is very fair of you - DFranklin indicated you should break down the area under the graph into rectangles and triangles and you responded with a graph that didn’t do that.
I don’t think that is very fair of you - DFranklin indicated you should break down the area under the graph into rectangles and triangles and you responded with a graph that didn’t do that.
At the same time, I would fully accept I was pretty harsh, but it feels nothing actually gets through to the OP. It's always "yes, you're right, I'll do that", and then in the very next post, they go back to the same behaviour.
They have been giving you help, you just aren’t doing the steps they ask you to do.
The forums are not meant to replace school/tutors by teaching you to topics-they are simply to give a guiding hand.
The forums are not meant to replace school/tutors by teaching you to topics-they are simply to give a guiding hand.
Part of my frustration (which I suspect is shared by other heavy contributors) is that it doesn't feel the OP actually values the help. Oh, they say they do, but they can't be bothered to read responses, or post their thoughts, or make diagrams where they actually bother to use a ruler. I can't help feeling if they were paying cold hard cash they might be a little more mindful of the need to actually put some effort in themselves.
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I completely understand that. And iam very well aware and iam not asking for more than a guiding hand. I have had extremely helpful discussions and people taking extra steps to help me out. only request is if someone can't help they can very politely deny or just not respond. iam very well aware that if someone is helping me out they are investing their valuable time and I respect that. Thanks!!
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#17
(Original post by Shas72)
I completely understand that. And iam very well aware and iam not asking for more than a guiding hand. I have had extremely helpful discussions and people taking extra steps to help me out. only request is if someone can't help they can very politely deny or just not respond. iam very well aware that if someone is helping me out they are investing their valuable time and I respect that. Thanks!!
I completely understand that. And iam very well aware and iam not asking for more than a guiding hand. I have had extremely helpful discussions and people taking extra steps to help me out. only request is if someone can't help they can very politely deny or just not respond. iam very well aware that if someone is helping me out they are investing their valuable time and I respect that. Thanks!!
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iam not willing to continue this discussion as its leading nowhere. My only request is don't throw your frustration by being nasty. if somebody isn't understanding my advise I would just stop responding. As iam reiterating I have had very very encouraging and very very helpful discussions on this forum. I respect the way people invest their time giving a helping hand on this forum. Thanks anyways
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#19
(Original post by Shas72)
I understood how to get the expression 40+20(t-4). I don't understand how is it 22(t-10)-1/2(t-10)^2
I understood how to get the expression 40+20(t-4). I don't understand how is it 22(t-10)-1/2(t-10)^2
(Original post by Shas72)
I did that already. I don't understand how to get the expression 22(t-10)-1/2(t-10)^2. if possible pls show me a few steps. I will work on it
I did that already. I don't understand how to get the expression 22(t-10)-1/2(t-10)^2. if possible pls show me a few steps. I will work on it
Can you see from the graph where the number 220 comes from in the formula for the truck's distance, i.e. which section of the graph it corresponds to?
What part of the graph represents the remaining distance? What steps would you carry out to calculate that distance?
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(Original post by davros)
What does your graph for the truck look like (plotted up to a time t which is greater than 10)?
Can you see from the graph where the number 220 comes from in the formula for the truck's distance, i.e. which section of the graph it corresponds to?
What part of the graph represents the remaining distance? What steps would you carry out to calculate that distance?
What does your graph for the truck look like (plotted up to a time t which is greater than 10)?
Can you see from the graph where the number 220 comes from in the formula for the truck's distance, i.e. which section of the graph it corresponds to?
What part of the graph represents the remaining distance? What steps would you carry out to calculate that distance?
Last edited by Shas72; 1 month ago
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