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Q: http://prntscr.com/vs5g3k
What does the "diameter of the centre" even mean? Are all the shaded sectors part of a sector from the same circle?. Here is how I interpreted it: http://prntscr.com/vs5ig9
What does the "diameter of the centre" even mean? Are all the shaded sectors part of a sector from the same circle?. Here is how I interpreted it: http://prntscr.com/vs5ig9
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(Original post by Justvisited)
Your two diagrams contradict each other.
Your two diagrams contradict each other.
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#5
The (part of) sector radius is 1.8, not 2.2.
Apart from that, it looks ok.
Apart from that, it looks ok.
Last edited by mqb2766; 1 month ago
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#6
(Original post by TSR360)
How?
How?
I believe the length you have labelled as 2.2 should be 1.8
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#7
(Original post by TSR360)
Q: http://prntscr.com/vs5g3k
What does the "diameter of the centre" even mean? Are all the shaded sectors part of a sector from the same circle?. Here is how I interpreted it: http://prntscr.com/vs5ig9
Q: http://prntscr.com/vs5g3k
What does the "diameter of the centre" even mean? Are all the shaded sectors part of a sector from the same circle?. Here is how I interpreted it: http://prntscr.com/vs5ig9
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(Original post by the bear)
the centre is circular therefore it has a diameter
the centre is circular therefore it has a diameter
What did I do wrong? If it's in radians, do I keep the RAD mode on in my calculator even if I'm not dealing with angles? I tried that but I still get the wrong answer http://prntscr.com/vs7ft7
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#9
(Original post by TSR360)
Here's my w/o: http://prntscr.com/vs742i
What did I do wrong? If it's in radians, do I keep the RAD mode on in my calculator even if I'm not dealing with angles? I tried that but I still get the wrong answer http://prntscr.com/vs7ft7
Here's my w/o: http://prntscr.com/vs742i
What did I do wrong? If it's in radians, do I keep the RAD mode on in my calculator even if I'm not dealing with angles? I tried that but I still get the wrong answer http://prntscr.com/vs7ft7
If you add the 4 sectors together you get a (part of) semi circle. Can't see why you'd particularly use radians.
Last edited by mqb2766; 1 month ago
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#10
Area of big circle = 𝝅 x 2.22
the shaded bits can be joined up to make a semicircle with a small semicircle removed:
grey semicircle area = 𝝅 x 1.82/2
small semicircle area = 𝝅 x 0.52/2
area of shaded bits = 𝝅 x 1.82/2 - 𝝅 x 0.52/2
Area of metal = Area of big circle - area of shaded bits....
once you know the area of metal you can then find its volume.
the shaded bits can be joined up to make a semicircle with a small semicircle removed:
grey semicircle area = 𝝅 x 1.82/2
small semicircle area = 𝝅 x 0.52/2
area of shaded bits = 𝝅 x 1.82/2 - 𝝅 x 0.52/2
Area of metal = Area of big circle - area of shaded bits....
once you know the area of metal you can then find its volume.
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(Original post by mqb2766)
What is c2? Radius seems way too large?
If you add the 4 sectors together you get a (part of) semi circle. Can't see why you'd particularly use radians.
What is c2? Radius seems way too large?
If you add the 4 sectors together you get a (part of) semi circle. Can't see why you'd particularly use radians.
Last edited by TSR360; 1 month ago
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#12
(Original post by TSR360)
c2 is the circle around the 4 shaded segments. I can only get the right answer if I leave RAD mode on and do all my calculations with radians, why is that?
c2 is the circle around the 4 shaded segments. I can only get the right answer if I leave RAD mode on and do all my calculations with radians, why is that?
See the bears post for simply adding/subtracting 3 circles and semi circles.It's the easiest way.
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