agape_99
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need help on this vertical motion's question!!

"A ball is projected vertically upwards from a point that is 6m above the ground. The ball reaches a maximum height of 13m above the ground during its flight, before coming to rest on the ground. Find the total time of flight of the ball"
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RogerOxon
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(Original post by agape_99)
"A ball is projected vertically upwards from a point that is 6m above the ground. The ball reaches a maximum height of 13m above the ground during its flight, before coming to rest on the ground. Find the total time of flight of the ball"
Use the maximum height that is reached (above the start point) to calculate the ball's initial, upward speed (v^2=u^2+2as). Then calculate the time of flight by solving s=ut+at^2/2. Note that you should get one negative and one positive solution. Also be aware that SUVAT implicitly assumes that s=0 at t=0. Be careful to apply your convention for the positive direction consistently.

Please post your working if you have any issues.
Last edited by RogerOxon; 1 month ago
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agape_99
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Yep got it now. That's really helpful, thank you!!
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