Vertical motion (mass and weight/gravity)
A stone of mass m is released from rest on the surface of a tank of water of depth d. During the motion, the water exerts a constant resisting force of magnitude R. The stone takes t seconds to reach the bottom of the tank. Show that R = m(g - 2d/t^2).
What have you got so far? 
Start with a diagram and suvat information
Original post by jduxie4414
What have you got so far?
Original post by agbotse.joana
A stone of mass m is released from rest on the surface of a tank of water of depth d. During the motion, the water exerts a constant resisting force of magnitude R. The stone takes t seconds to reach the bottom of the tank. Show that R = m(g - 2d/t^2).
Just to get you going, draw a free body force diagram to consider the forces on the sphere. Then use F = ma. To find a you can use SUVAT!
If you expand the equation in R, you get R = mg - 2md/t^2. Can you think of what mg is?
(edited 3 years ago)
Quick Reply
Related discussions
- Maths Further ( Mechanics)
- A-Level Mechanics Help
- Mechanics help
- m1 mechanics as vectors 2018 internation edexcel q6
- Physics question
- as level mechanics suvat
- Circular motion
- vertical motion- max height
- A level physics
- FM-m2-circular motion
- IAL Edexcel Jan 2019 Mech2 Q8b(ii) & 8c
- Physics question suvat
- A vehicle accelerates uniformly...
- Help mechanics
- M2 projectile Q help
- acceleration on an angle
- Vectors with mechanics question
- As mechanics question
- AS Mechanics
- Force Diagram (A2 Edexcel)
Latest
Trending
Last reply 4 days ago
Edexcel A Level Politics Paper 1 (9PL0 01) - 21st May 2024 [Exam Chat]Trending
Last reply 4 days ago
Edexcel A Level Politics Paper 1 (9PL0 01) - 21st May 2024 [Exam Chat]
