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Inverse Hyperbolic Functions

Hiya - I've attached a page from my FM textbook about solving hyperbolic equations using the inverse.

A third of the way down it says 'the two roots of the equation are shown on the graph below' - however I don't understand this. The y=cosh(x) curve is clearly above the x-axis, so how does it have two roots? :confused:
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Original post by beachpanda
Hiya - I've attached a page from my FM textbook about solving hyperbolic equations using the inverse.

A third of the way down it says 'the two roots of the equation are shown on the graph below' - however I don't understand this. The y=cosh(x) curve is clearly above the x-axis, so how does it have two roots? :confused:

The equation in question is cosh(x) = 2.
Reply 2
Avatar for beachpanda
beachpanda
OP
13
Original post by DFranklin
The equation in question is cosh(x) = 2.

I see, is that not just the same as y = 2 ?
Reply 3
Avatar for Sinnoh
Sinnoh
22
Original post by beachpanda
I see, is that not just the same as y = 2 ?


y = 2 is the equation of the line. cosh(x) = 2 is the actual equation to solve. That graph shows where the graph of y = cosh(x) crosses the graph of y = 2.

Or you can rewrite it as cosh(x) - 2 = 0 if that makes more sense.
Reply 4
Avatar for beachpanda
beachpanda
OP
13
Original post by Sinnoh
y = 2 is the equation of the line. cosh(x) = 2 is the actual equation to solve. That graph shows where the graph of y = cosh(x) crosses the graph of y = 2.

Or you can rewrite it as cosh(x) - 2 = 0 if that makes more sense.


Ahh right I get it, thanks!

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