Trig question a level maths

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#1
If tan(x) = -7/24 and x is obtuse, find the value of tan(x/2)
This may end up being really simple but I’m currently making no progress with it
I was thinking of using one of the trig identities but I’m not too sure
Any help would be appreciated
0
1 month ago
#2
(Original post by helloworld121)
If tan(x) = -7/24 and x is obtuse, find the value of tan(x/2)
This may end up being really simple but I’m currently making no progress with it
I was thinking of using one of the trig identities but I’m not too sure
Any help would be appreciated
Would tan 2A =( 2 tan A)/(1 - tan^2 A) help?
0
1 month ago
#3
Since tan(x) is obtuse then it is between 180 and 90. As tan(x)=-7/24, then to find x we do tan^-1(-7/24) which is equal to x so if we do 180 - tan^-1(-7/24) we get the obtuse angle which is x. Now if you keep x as an answer in your calculator then we do tan(ANS/2) which is tan(x/2) and that is your answer.
Tan^-1 is inverse tan.
(Edit: An obtuse angle is between 180 and 90)
Hope this helped
Last edited by a0mp; 1 month ago
0
1 month ago
#4
(Original post by helloworld121)
If tan(x) = -7/24 and x is obtuse, find the value of tan(x/2)
This may end up being really simple but I’m currently making no progress with it
I was thinking of using one of the trig identities but I’m not too sure
Any help would be appreciated
tan2x=2tanx/1-tan^2x
Use tanx in place of tan2x
0
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