completing the squareWatch
Step 1) Whenever there is a number infront of an ‘x’ you can half it and put it in the brackets of (x ...)^2 Where the “...” is the halved number.
Step2) using this halved number e.g 3 (from the image, we always subtract the square of it. So in this case 3 squared is 9 so we add “-9” to our equation.
Finally we bring down the constant “10” or anything that isn’t with an ‘X’ with it.
We can then do -9 10 giving us -1.
Therefore our final equation is :
(x 3)^2 -1
Is pretty good.
Just to make it clear I made a mistake. And the following image is the correct one.