# Maths

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#1

Struggling on this, there’s no solutions for it too
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1 month ago
#2

Struggling on this, there’s no solutions for it too
e^2x = (u-1)^2
Which is the numerator. Should be straightforward to integrate wrt u?
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#3
(Original post by mqb2766)
e^2x = (u-1)^2
Which is the numerator. Should be straightforward to integrate wrt u?
Done - I get {integral} (u-1)^2 / u ?
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#4
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1 month ago
#5

The working is a bit wrong (cubic?), but the previous answer is right, so maybe a typo.
It's a quadratic numerator after cancelling by e^x.
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#6
(Original post by mqb2766)
The working is a bit wrong (cubic?), but the previous answer is right, so maybe a typo.
It's a quadratic numerator after cancelling by e^x.
I’m confused, so I was right?

e^3x is (u-1)^2

So I made everything in terms of u ,
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1 month ago
#7
I’m confused, so I was right?

e^3x is (u-1)^2

So I made everything in terms of u ,
No. Why do you think that?
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#8
(Original post by mqb2766)
No. Why do you think that?
I mean (u-1)^3*
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1 month ago
#9
I mean (u-1)^3*
Yes. It was slightly easier to cancel e^x first, then do the quadratic x->u substitution.
Last edited by mqb2766; 1 month ago
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#10
(Original post by mqb2766)
Yes. It was slightly easier co cancel e^x first, then do the quadratic substitution.
u(u-1)^4 / u (u-1) ?
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1 month ago
#11
u(u-1)^4 / u (u-1) ?
I have no idea where you're going with this. You seem to be doing random algebra.
Just continue #3.
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#12
(Original post by mqb2766)
I have no idea where you're going with this.
Just continue #3.
🤣🤣🤣🤣🤣
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#13
(Original post by mqb2766)
I have no idea where you're going with this. You seem to be doing random algebra.
Just continue #3.
I’m confuzzeld😂😂

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1 month ago
#14
I’m confuzzeld😂😂

You must have understood how you got to post 3? Then simply integrate.
If not, describe what the problem is, I'm thoroughly confused what you're trying to do.
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#15
(Original post by mqb2766)
You must have understood how you got to post 3? Then simply integrate.
If not, describe what the problem is, I'm thoroughly confused what you're trying to do.
Ahhh! I seee it!!!
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#16
(Original post by mqb2766)
You must have understood how you got to post 3? Then simply integrate.
If not, describe what the problem is, I'm thoroughly confused what you're trying to do.
Oh my goodness, hold on pls
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1 month ago
#17
Oh my goodness, hold on pls
Can hardly wait ...
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#18
(Original post by mqb2766)
Can hardly wait ...
So it’s 1/u right?

I got {integral} 1/u + (u-1)^3 / (u-1) du
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1 month ago
#19
So it’s 1/u right?

I got {integral} 1/u + (u-1)^3 / (u-1) du
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#20
(Original post by mqb2766)
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