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Help with chemistry as please

What is the empirical formula of an oxide of nitrogen that contains 26% nitrogen by mass?

I got NO2, but the answer is N2O5 help plz
Reply 1
26% Nitrogen (Ar=14) so there must be 74% Oxygen (Ar = 16).

Moles of N is therefore: 26/14
Moles of O is therefore 74/16
(Remember that moles = Mass / Ar)

Now simplify the molar ratio:
(26/14) : (74/16)
1.857 : 4.624
1 : 2.5
2 : 5

= N2O5 :smile:
(edited 3 years ago)

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