a level chemistry help? (aqa)
i've been looking at some questions on NMR and one asks to "write a half-equation for the reduction of dichromate(VI) ions in acidic solution".
the mark scheme says that the eqn is:
6e- + 14H+ Cr2O7^2- --> 2Cr^3+ + 7H2O
how would i know that the dichromate ion is reduced to Cr^3+ without the question telling me in advanced?
the mark scheme says that the eqn is:
6e- + 14H+ Cr2O7^2- --> 2Cr^3+ + 7H2O
how would i know that the dichromate ion is reduced to Cr^3+ without the question telling me in advanced?
Original post by kierab22
i've been looking at some questions on NMR and one asks to "write a half-equation for the reduction of dichromate(VI) ions in acidic solution".
the mark scheme says that the eqn is:
6e- + 14H+ Cr2O7^2- --> 2Cr^3+ + 7H2O
how would i know that the dichromate ion is reduced to Cr^3+ without the question telling me in advanced?
the mark scheme says that the eqn is:
6e- + 14H+ Cr2O7^2- --> 2Cr^3+ + 7H2O
how would i know that the dichromate ion is reduced to Cr^3+ without the question telling me in advanced?
Dichromate(VI) in acid is a common oxidising agent in organic chemistry. You are probably expected to know that it is used to oxidise alcohols to aldehydes/ketones and then to carboxylic acids (aldehydes)
Original post by kierab22
i've been looking at some questions on NMR and one asks to "write a half-equation for the reduction of dichromate(VI) ions in acidic solution".
the mark scheme says that the eqn is:
6e- + 14H+ Cr2O7^2- --> 2Cr^3+ + 7H2O
how would i know that the dichromate ion is reduced to Cr^3+ without the question telling me in advanced?
the mark scheme says that the eqn is:
6e- + 14H+ Cr2O7^2- --> 2Cr^3+ + 7H2O
how would i know that the dichromate ion is reduced to Cr^3+ without the question telling me in advanced?
You have to just know it. Just like you need to know manganate ions are reduced to Mn2+ ions, and many others
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