15mohsinfa
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write an equation for the complete combustion of alkane, which requires 14 moles of oxygen gas for each mole of Alkane combusted
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pineapple201
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Can you send me the link to the question?
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Abhi321
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So I think it goes something like this:
The basic equation for complete combustion of an alkane should be:
C(n)H(2n+2) + (x)O2 = nCO2 + (n+1)H2O
(x) = 2n + n+1 = 3n+1
So since 14 O2 is used you can use the above
14x2 (since theres 14 moles of O2) = 3n+1
Therefore n=9
Therefore the alkane is C9H20
The equation is C9H20 + 14O2 = 9CO2 + 10H2O
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15mohsinfa
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(Original post by Abhi321)
So I think it goes something like this:
The basic equation for complete combustion of an alkane should be:
C(n)H(2n+2) + (x)O2 = nCO2 + (n+1)H2O
(x) = 2n + n+1 = 3n+1
So since 14 O2 is used you can use the above
14x2 (since theres 14 moles of O2) = 3n+1
Therefore n=9
Therefore the alkane is C9H20
The equation is C9H20 + 14O2 = 9CO2 + 10H2O
thank you so much!!!!!!!!!!!!!!!
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Abhi321
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Your welcome.
I hope I didn’t confuse you too much 🤗
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