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# hELLPpppppppppppppppP Chemistry Problem :( watch

1. What is the total number of moles of particles(ions, molecules) present in 0.35 mol of Copper (II) sulphate-5-water, CuSO4.5H2O

realllyy confused
sum1 pleaseeeeeeee show me the steps
2. How did i know it would be you

Odd question are you sure thats word for word?
3. if 1 mol contains 6.02 x 10^23 molecules (avogadro's number), then 0.35 mole contains X, simple mathematics, cross multiply.
the answer is 2.107 x 10^23 molecules
4. I'm not far enough into my course to know what the . means, ordinarily the CuSO4 is just a solute, what is its relationship to water when its written CuSO4.5H2O? Surely its more complicated than above, thats kind of easy and the question is written in a more complex format...
5. (Original post by LearningMath)
what is its relationship to water when its written CuSO4.5H2O?
The water just show that it's hydrated copper (II) sulphate - the normal blue kind) - rather than anhydrous (white powder).
6. (Original post by A.J.B)
if 1 mol contains 6.02 x 10^23 molecules (avogadro's number), then 0.35 mole contains X, simple mathematics, cross multiply.
the answer is 2.107 x 10^23 molecules
what he said ^^
7. What a stupid question. Thought it was gona be interesting
8. we've all had those moments mate, its ok!

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