Help - Isaac Physics - Discharging Capacitor

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fastnfuriouseng
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Hiya!
I would be grateful for any help on part d of the Discharging Capacitor Isaac Physics Question.

Question:
In the circuit below, the capacitor is initially holding a charge of Q_0. The capacitance of the capacitor is C and the resistors have values R_1 and R_2.

Name:  IsaacPhysics_DischargingCapacitor_Schematic.PNG
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Part A:
Name:  IsaacPhysics_DischargingCapacitor_PartA.PNG
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Part B:
Name:  IsaacPhysics_DischargingCapacitor_PartB.PNG
Views: 18
Size:  18.0 KB
Part C:
Name:  IsaacPhysics_DischargingCapacitor_PartC.PNG
Views: 14
Size:  44.8 KB

Part D:
At the point when the capacitor is holding a charge of Q how much energy has been dissipated in R_2?

I have looked at all of the hints but don't know where to start.
Last edited by fastnfuriouseng; 2 weeks ago
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fastnfuriouseng
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Hiya!
I would be grateful for any help on part d of the Discharging Capacitor Isaac Physics Question.

Question:
In the circuit below, the capacitor is initially holding a charge of Q_0. The capacitance of the capacitor is C and the resistors have values R_1 and R_2.

Name:  IsaacPhysics_DischargingCapacitor_Schematic.PNG
Views: 11
Size:  4.1 KB

Part A:
Name:  IsaacPhysics_DischargingCapacitor_PartA.PNG
Views: 6
Size:  14.7 KB

Part B:
Name:  IsaacPhysics_DischargingCapacitor_PartB.PNG
Views: 7
Size:  18.0 KB

Part C:
Name:  IsaacPhysics_DischargingCapacitor_PartC.PNG
Views: 7
Size:  44.8 KB

Part D:
At the point when the capacitor is holding a charge of Q how much energy has been dissipated in R_2?

I have looked at all of the hints but don't know where to start.
Last edited by fastnfuriouseng; 2 weeks ago
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Eimmanuel
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(Original post by fastnfuriouseng)
Hiya!
I would be grateful for any help on part d of the Discharging Capacitor Isaac Physics Question.

Question:
In the circuit below, the capacitor is initially holding a charge of Q_0. The capacitance of the capacitor is C and the resistors have values R_1 and R_2.

Name:  IsaacPhysics_DischargingCapacitor_Schematic.PNG
Views: 18
Size:  4.1 KB
Part A:
Name:  IsaacPhysics_DischargingCapacitor_PartA.PNG
Views: 14
Size:  14.7 KB
Part B:
Name:  IsaacPhysics_DischargingCapacitor_PartB.PNG
Views: 18
Size:  18.0 KB
Part C:
Name:  IsaacPhysics_DischargingCapacitor_PartC.PNG
Views: 14
Size:  44.8 KB

Part D:
At the point when the capacitor is holding a charge of Q how much energy has been dissipated in R_2?

I have looked at all of the hints but don't know where to start.
Don't abuse the forum by duplicating thread. Restrict the question within the original thread and don't bump the thread in less than 1 day.
Read the forum posting guidelines.

As for your question, you need the graph of Figure 10.39(d) in the following link.
https://openstax.org/books/universit...-5-rc-circuits

The voltage across R2 decreases exponentially and you can use the following expression to find the energy has been dissipated in R_2:
 E = \dfrac{V^2}{R_2} \Delta t
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fastnfuriouseng
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(Original post by Eimmanuel)
Don't abuse the forum by duplicating thread. Restrict the question within the original thread and don't bump the thread in less than 1 day.
Read the forum posting guidelines.

As for your question, you need the graph of Figure 10.39(d) in the following link.
https://openstax.org/books/universit...-5-rc-circuits

The voltage across R2 decreases exponentially and you can use the following expression to find the energy has been dissipated in R_2:
 E = \dfrac{V^2}{R_2} \Delta t
Sorry! I just made a mistake in my first message and tried clearing it and thought it wouldn't pop up anymore.

Thank you for your help! However, I tried using the equation you have given and don't seem to get the correct answer...I used the previous parts and simplified to getName:  IsaacPhysics_DischargingCapacitor_PartD.PNG
Views: 7
Size:  54.0 KB

Could you please help me out a bit more?
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Eimmanuel
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(Original post by fastnfuriouseng)
Sorry! I just made a mistake in my first message and tried clearing it and thought it wouldn't pop up anymore.

Thank you for your help! However, I tried using the equation you have given and don't seem to get the correct answer...I used the previous parts and simplified to getName:  IsaacPhysics_DischargingCapacitor_PartD.PNG
Views: 7
Size:  54.0 KB

Could you please help me out a bit more?
How do you use the equation?

Spoiler:
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The voltage across R2 is NOT constant. This means that the equation can be applied directly.
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fastnfuriouseng
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(Original post by Eimmanuel)
How do you use the equation?

Spoiler:
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The voltage across R2 is NOT constant. This means that the equation can be applied directly.
I squared the initial voltage (see part A) and divided this by R_2 and multiplied it by delta v (see part C). Could you maybe give me an extra pointer? I am stuck am not that sure how to use the formula correctly....
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Eimmanuel
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(Original post by fastnfuriouseng)
I squared the initial voltage (see part A) and divided this by R_2 and multiplied it by delta v (see part C). Could you maybe give me an extra pointer? I am stuck am not that sure how to use the formula correctly....
I did mention in post #3 that you need graph in Fig10.39(d). The graph in Fig10.39(d) allows you write an expression of voltage across R2 and you need to square this expression.
The last crucial part is using calculus in the following formula.

 E = \dfrac{V^2}{R_2} \Delta t
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