Core 1 help Please Watch

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m66
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#1
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#1
1) Make l the subject of the formula T = 2pi sqrt l/g
(that is t equals 2pi times the sqr root of l over g)

2) simplify x^5/2 x x^1/2
(that is x to the power of 5 over 2 times sqr root of x)
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Nima
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#2
Report 14 years ago
#2
(Original post by m66)
1) Make l the subject of the formula T = 2pi sqrt l/g
(that is t equals 2pi times the sqr root of l over g)

2) simplify x^5/2 x x^1/2
(that is x to the power of 5 over 2 times sqr root of x)
1) T = 2pi sqrt l/g
---> T^2 = 4Pi^2l/g
---> l = (T^2g)/(4Pi^2)

2) x^(5/2) . x^(1/2) = x^(5/2 + 1/2) = x^(6/2) = x^3
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