limitlesspuffy
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#1
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I don't understand how in this picture, the name of this compound is 3-ethyl...
Shouldn't it be 2-ethyl?
Because if you count from the double bond then it's on the 2nd Carbon. How is it 3?
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limitlesspuffy
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(Original post by TrES2b)
the ethyl group is on the 3rd carbon counting from right to left
but if we count that way then it doesn't take in count the double bond. Do we not have to use the same numbering throughout?
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TrES2b
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(Original post by limitlesspuffy)
but if we count that way then it doesn't take in count the double bond. Do we not have to use the same numbering throughout?
let me show you what i mean

one seconf pls
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TrES2b
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(Original post by TrES2b)
let me show you what i mean

one seconf pls
hii pls check this
Last edited by TrES2b; 1 month ago
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limitlesspuffy
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(Original post by TrES2b)
hii pls check this
soo the methyl group is on the 2nd C and ethyl group is on the 5th C?
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ilovephysmath
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you start counting from the side closest to the double bonds. according to that convention, you're correct. it should be 2-ethyl
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TrES2b
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(Original post by limitlesspuffy)
soo the methyl group is on the 2nd C and ethyl group is on the 5th C?
did you get my image?

basically for nomenclature you must but it in alpha numerical order where possible


look at this picture (sorry for lots of images im trying to explain this as best as i can)

so the blue is where we count from right to left this would give : 2- ethyl 5 methyl

but if you counted with the red numbers it would give 2- methyl and 5 ethyl

and because e comes before m you have to go with the one that is in alpha numerical order

sorry does this make sense, does it answer your question?
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ilovephysmath
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this is 2-ethyl..... if you rotate it you'll see it's the same as the displayed formula in the diagram you've shown. it could be a typo?
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limitlesspuffy
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(Original post by TrES2b)
did you get my image?

basically for nomenclature you must but it in alpha numerical order where possible


look at this picture (sorry for lots of images im trying to explain this as best as i can)

so the blue is where we count from right to left this would give : 2- ethyl 5 methyl

but if you counted with the red numbers it would give 2- methyl and 5 ethyl

and because e comes before m you have to go with the one that is in alpha numerical order

sorry does this make sense, does it answer your question?
Oh okayy tysm for your help! I got confused because the answer said it was 3-ethyl not 2-ethyl
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limitlesspuffy
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(Original post by ilovephysmath)
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this is 2-ethyl..... if you rotate it you'll see it's the same as the displayed formula in the diagram you've shown. it could be a typo?
Thank youu I think it must be a typo then!
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TrES2b
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(Original post by limitlesspuffy)
Oh okayy tysm for your help! I got confused because the answer said it was 3-ethyl not 2-ethyl
ohhh yes yes the answer is wrong LMAOO i thought you were asking why its wrong but yeah its 2 ethyl
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limitlesspuffy
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(Original post by TrES2b)
ohhh yes yes the answer is wrong LMAOO i thought you were asking why its wrong but yeah its 2 ethyl
sorry for the confusion loll😂
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TrES2b
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(Original post by limitlesspuffy)
sorry for the confusion loll😂
nope nope youre all good i misread your post!! hope its all good tho!
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