Ailurophile03
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#1
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#1
i am not sure
im assuming the asnwer to be y=mx-2
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scottishpenguin
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#2
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I can't even read the first bit of the question, could you type it in?
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Ailurophile03
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#3
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(Original post by scottishpenguin)
I can't even read the first bit of the question, could you type it in?
sorry about that, it says ashbourne ice house if offering a discount of 2$
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Ailurophile03
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ghostwalker
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#5
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(Original post by Ailurophile03)
i am not sure
im assuming the asnwer to be y=mx-2
Depends on what they want.

Good so far, but you can go a stage further than that. What would m be?
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Ailurophile03
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(Original post by ghostwalker)
Depends on what they want.

Good so far, but you can go a stage further than that. What would m be?
i really have no idea how i can find m
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ghostwalker
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#7
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(Original post by Ailurophile03)
i really have no idea how i can find m
Well, if x is the regular price, and you knock $2 off for discount, what's the new price?
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Ailurophile03
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#8
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(Original post by ghostwalker)
Well, if x is the regular price, and you knock $2 off for discount, what's the new price?
x-2
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ghostwalker
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(Original post by Ailurophile03)
x-2
Fine,

Compare that with "mx-2"

What's m?
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Ailurophile03
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#10
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(Original post by ghostwalker)
Fine,

Compare that with "mx-2"

What's m?
1 as ×-2=0 so x=2 so m(2)-2=0 so m=1
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ghostwalker
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#11
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(Original post by Ailurophile03)
1 as ×-2=0 so x=2 so m(2)-2=0 so m=1
Yes, m=1.

You could also just note that mx-2 and x-2 are identical (the same function), so m must be 1.
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