1.) A particle of weight W newtons is attached at C to the ends of 2 light inextensible strings AC & BC. The other ends of the strings are attached to two fixed points A & B on a horizontal ceiling. The particle hangs in equilibrium with AC & BC inclined to the horizontal at 30º and 60º respectively as shown below. Given that the tension in AC is 50N, calculate,
1.) A particle of weight W newtons is attached at C to the ends of 2 light inextensible strings AC & BC. The other ends of the strings are attached to two fixed points A & B on a horizontal ceiling. The particle hangs in equilibrium with AC & BC inclined to the horizontal at 30º and 60º respectively as shown below. Given that the tension in AC is 50N, calculate,
a.) the tension in BC to 3 sig fig.
b.) the value of W.
Many thanks.
1)a Resolve forces horizontally as W is unknown. Tcos60 - 50cos30 = 0 T = (50cos30)/cos60 = 86.6N
1)b Resolve forces vertically 50sin30 + 86.603sin60 = W W = 100N