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    Bah. I forget how to do these.

    1.) A particle of weight W newtons is attached at C to the ends of 2 light inextensible strings AC & BC. The other ends of the strings are attached to two fixed points A & B on a horizontal ceiling. The particle hangs in equilibrium with AC & BC inclined to the horizontal at 30º and 60º respectively as shown below. Given that the tension in AC is 50N, calculate,

    a.) the tension in BC to 3 sig fig.

    b.) the value of W.

    Many thanks.
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    (Original post by Slice'N'Dice)
    Bah. I forget how to do these.

    1.) A particle of weight W newtons is attached at C to the ends of 2 light inextensible strings AC & BC. The other ends of the strings are attached to two fixed points A & B on a horizontal ceiling. The particle hangs in equilibrium with AC & BC inclined to the horizontal at 30º and 60º respectively as shown below. Given that the tension in AC is 50N, calculate,

    a.) the tension in BC to 3 sig fig.

    b.) the value of W.

    Many thanks.
    1)a
    Resolve forces horizontally as W is unknown.
    Tcos60 - 50cos30 = 0
    T = (50cos30)/cos60 = 86.6N

    1)b
    Resolve forces vertically
    50sin30 + 86.603sin60 = W
    W = 100N

    P.S Love the avatar!
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    Hehe

    Thanks for the help WM. I was resolving the wrong way! :eek:

    :hello:
 
 
 
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