Explain what problems may arise if you use the Newton-Raphson methodWatch
The diagram is wrong. Just "reverse" the first diagram (the function is ~ symmetrical). x2 should be the first value and the next point (their x2) should be vertically above the axis crossing point as you say. The gradient at the first point would have to be smaller (move it slightly right), so the crossing point (second point) is to the left of the minimum point.