pearllx
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A parcel of mass 8 kg rests on a smooth slope, and is connected by a light inextensible string which passes over a smooth pulley to a mass of 2kg, which hangs freely. The system is in equilibrium. Find the angle of the slope.


I have no idea how to answer this question any help is appreciated
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physgradstudent
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Have you tried sketching a free body diagram for both masses?
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pearllx
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(Original post by physgradstudent)
Have you tried sketching a free body diagram for both masses?
Yes
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szczesniak
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When the system is in equilibrium, the tension in both end of string is the same. Hence, the tension to the "right" of pulley = the tension to the "left" of pulley.

If you sketched the diagram properly, it should be straightforward from now on. Denote the angle as theta. Now you gotta set up a single inequality, that is, the weight of a mass freely hanging = the component of weight of a mass (that is resting on a smooth slope) parallel to the slope. Then you solve that inequality for theta, and get your answer.
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pearllx
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(Original post by szczesniak)
When the system is in equilibrium, the tension in both end of string is the same. Hence, the tension to the "right" of pulley = the tension to the "left" of pulley.

If you sketched the diagram properly, it should be straightforward from now on. Denote the angle as theta. Now you gotta set up a single inequality, that is, the weight of a mass freely hanging = the component of weight of a mass (that is resting on a smooth slope) parallel to the slope. Then you solve that inequality for theta, and get your answer.
Ahh I see I got the correct answer as I checked the answers, I’m not really good at mechanics but thank u
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