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I need help with this Physics End of Chapter Test. Thanks
Two cars are involved in a head-on collision.
a State two quantities conserved in the collision. [2]
b The collision between the cars is described as an inelastic collision.
Explain what is meant by an inelastic collision. [2]
2 A car of mass 1200 kg is travelling along a straight road at a velocity of 25 m s−1
.
The driver applies the brakes for a duration of 2.0 s.
During this interval, the car decelerates with a magnitude of 4.0 m s−2
.
Calculate the change in the momentum of the car. [3]
3 A 2.8-tonne lorry moving at a speed of 30 m s−1
collides into the back of a stationary car
of mass 800 kg on the hard shoulder of the motorway.
During the collision, the lorry and the car get tangled together.
a Calculate the common speed V of the tangled lorry and car. [4]
b Calculate the loss of kinetic energy in the collision. [3]
4 A bumper car of mass 300 kg moving at 4.0 m s−1
collides with another bumper car of mass
420 kg moving at 1.5 m s−1 in the opposite direction.
After the collision, the speed of the 300 kg car decreases to 0.50 m s−1
but it carries on moving
in the same direction (see diagram).
Determine the speed v and the direction of the 420 kg bumper car after the collision.
Two cars are involved in a head-on collision.
a State two quantities conserved in the collision. [2]
b The collision between the cars is described as an inelastic collision.
Explain what is meant by an inelastic collision. [2]
2 A car of mass 1200 kg is travelling along a straight road at a velocity of 25 m s−1
.
The driver applies the brakes for a duration of 2.0 s.
During this interval, the car decelerates with a magnitude of 4.0 m s−2
.
Calculate the change in the momentum of the car. [3]
3 A 2.8-tonne lorry moving at a speed of 30 m s−1
collides into the back of a stationary car
of mass 800 kg on the hard shoulder of the motorway.
During the collision, the lorry and the car get tangled together.
a Calculate the common speed V of the tangled lorry and car. [4]
b Calculate the loss of kinetic energy in the collision. [3]
4 A bumper car of mass 300 kg moving at 4.0 m s−1
collides with another bumper car of mass
420 kg moving at 1.5 m s−1 in the opposite direction.
After the collision, the speed of the 300 kg car decreases to 0.50 m s−1
but it carries on moving
in the same direction (see diagram).
Determine the speed v and the direction of the 420 kg bumper car after the collision.
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(Original post by GabiAbi84)
Which parts do you need help with?
Which parts do you need help with?
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#5
(Original post by ollyeland)
question 2 onwards lol
question 2 onwards lol
What have you done so far?
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(Original post by Muttley79)
Post what you've tried ...
Post what you've tried ...
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#8
(Original post by ollyeland)
well at first I thought the answer was 25200, but im not sure
well at first I thought the answer was 25200, but im not sure
Where did you get that number from?
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#10
(Original post by ollyeland)
J = Δp = p₂ - p₁ = mv₂ - mv₁ = mΔv
J = Δp = p₂ - p₁ = mv₂ - mv₁ = mΔv
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(Original post by GabiAbi84)
Okay so what’s your figures for v1 and v2?
Okay so what’s your figures for v1 and v2?
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(Original post by GabiAbi84)
Okay so what’s your figures for v1 and v2?
Okay so what’s your figures for v1 and v2?
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#13
(Original post by ollyeland)
v1=25 v2=21 because decellerates by 4ms. Is the equation right?
v1=25 v2=21 because decellerates by 4ms. Is the equation right?
So a= -4
Last edited by GabiAbi84; 1 month ago
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(Original post by ollyeland)
yeh thats what i got
yeh thats what i got
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#16
(Original post by ollyeland)
yeh thats what i got
yeh thats what i got
You need to work out v2 using suvat
Last edited by GabiAbi84; 1 month ago
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