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Has anyone know how to do this question?(Good luck in your studies)
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A light elastic string AB, of natural length 0.5 m and modulus of elasticity 12 N, has a particle of mass
0.3 kg attached to B. The end A is attached to a fixed point at a distance of 0.7 m above a horizontal
table. The coefficient of restitution between the particle and the table is e. The particle is released
from rest at A, hits the table and rebounds to a height of 0.22 m above the table. Find the value of e,
assuming that there is no air resistance. Ans :1/3
0.3 kg attached to B. The end A is attached to a fixed point at a distance of 0.7 m above a horizontal
table. The coefficient of restitution between the particle and the table is e. The particle is released
from rest at A, hits the table and rebounds to a height of 0.22 m above the table. Find the value of e,
assuming that there is no air resistance. Ans :1/3
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Most important step is to find the velocity of the particle as it first strikes the table. I think this can be done through conservation of energy, with GPE being converted into kinetic and elastic potential energy.
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