roselover12334
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605𝜋 = 𝜋r^2(5)
what is the diameter
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danishh0007
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(Original post by roselover12334)
605𝜋 = 𝜋r^2(5)
what is the diameter
605pi/5pi=121

R^2=121. R=11
Diameter=11x2=22
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Rottero_A21
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(Original post by roselover12334)
605𝜋 = 𝜋r^2(5)
what is the diameter
Cancel out the pi’s on both sides... divide 605 by 5 and you’ll get 121.... r^2 = 121, r = +/- 11 (but we’re talking about length so it’s probably positive).

Diameter = 2(radius) = 22
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Gauthmath_iris
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First, r = sqrt(605/5)
and diameter = 2r
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