The Student Room Group

math

605đťś‹ = đťś‹r^2(5)
what is the diameter
Original post by roselover12334
605đťś‹ = đťś‹r^2(5)
what is the diameter


605pi/5pi=121

R^2=121. R=11
Diameter=11x2=22
Original post by roselover12334
605đťś‹ = đťś‹r^2(5)
what is the diameter

Cancel out the pi’s on both sides... divide 605 by 5 and you’ll get 121.... r^2 = 121, r = +/- 11 (but we’re talking about length so it’s probably positive).

Diameter = 2(radius) = 22
First, r = sqrt(605/5)
and diameter = 2r

Quick Reply

Latest