User000
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Help please!
A mixture of sodium oxide, Na2O, and barium oxide,BaO, that weighted 5.00g was dissolved in water. The resulting solution was treated with excess dilute sulfuric acid, H2SO4. Sulfuric acid converted the oxides to sulfates and barium sulfate precipitated from the solution. Sodium sulfate is soluble and remained in the solution.
The precipitate was filtered, dried and found to weigh 3.43g.
What percentage of the original sample was sodium oxide.
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GabiAbi84
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What have done with it so far?
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User000
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(Original post by GabiAbi84)
What have done with it so far?
Nothing I don’t know what to do with it
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Davies Chemistry
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See flow chart attached to help you
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User000
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(Original post by Davies Chemistry)
See flow chart attached to help you
Thank you very much
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User000
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(Original post by Davies Chemistry)
See flow chart attached to help you
It says the answer is 55% but I keep getting 30%
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GabiAbi84
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(Original post by User000)
It says the answer is 55% but I keep getting 30%
Post your calculations

The answer is definitely 55%
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User000
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(Original post by GabiAbi84)
Post your calculations

The answer is definitely 55%
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GabiAbi84
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(Original post by User000)
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You have rounded too early.

Your first calculation should end with 0.01469

Then the next one will be 2.25287

You need to make sure you keep more sig figures during your calculations.
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User000
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(Original post by GabiAbi84)
You have rounded too early.

Your first calculation should end with 0.01469

Then the next one will be 2.25287

You need to make sure you keep more sig figures during your calculations.
Thank you so much 😃
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Davies Chemistry
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(Original post by User000)
Thank you so much 😃
Good to know that your logic was sound and the error was just caused by the rounding!
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