anon25x
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#1
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Can someone explain please how to draw the structure of 1,3 dibromo-2-methylpropene ?
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tedibare
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firstly, you’ start with the basic chain and that is propene.
Write down 3 carbon atoms.
1,3 dibromo suggests that two bromine atoms are bonded to the 1st and 3rd carbon atom.
2methyl suggests that it’s on the 2nd carbon atom (methyl group is CH3)
Then just put your hydrogen atoms in the empty slots. Remember that one carbon atom can only have 4 bonds at a time. And a double bond counts as two
Last edited by tedibare; 7 months ago
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tedibare
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The double bond must be on the first carbon atom since it does not specify its position
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chloe0804
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So the main chain is propene which is three 3 atoms. It is alkene so you know there has to be a double c bond. Bromine on first C and then on the second C is a CH4 group (methyl) and then on last C is another Br. As it is symmetrical the double bond can go between either carbon 1&2 or carbon 2&3. Hope that helps
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anon25x
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(Original post by tedibare)
firstly, you’ start with the basic chain and that is propene.
Write down 3 carbon atoms.
1,3 dibromo suggests that two bromine atoms are bonded to the 1st and 3rd carbon atom.
2methyl suggests that it’s on the 2nd carbon atom (methyl group is CH3)
Then just put your hydrogen atoms in the empty slots. Remember that one carbon atom can only have 4 bonds at a time. And a double bond counts as two
(Original post by chloe0804)
So the main chain is propene which is three 3 atoms. It is alkene so you know there has to be a double c bond. Bromine on first C and then on the second C is a CH4 group (methyl) and then on last C is another Br. As it is symmetrical the double bond can go between either carbon 1&2 or carbon 2&3. Hope that helps
Thnk you I was thinking there'd be 3 carbon atoms but it's for e-z isomerism so I was a bit confused as to how i'd flip it?
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tedibare
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(Original post by Leemx)
Thnk you I was thinking there'd be 3 carbon atoms but it's for e-z isomerism so I was a bit confused as to how i'd flip it?
In that case, you only need 2 double bond carbon atoms, with CH3 bonded to 1st or second carbon.
Then you can put bromine on which E/Z isomer your looking for. E would be on opposite sides whilst Z would be on the same side. Know that ones with higher atomic number would be prioritised
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