# Modulus graphs question

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#1
Hi,
I've put the question I'm stuck on (part b) below and the answer - I don't know how to get that can someone please explain.
Thanks!

0
1 year ago
#2
with the function y =f(|x|) for any value of x, the y co-ordinate is the same as the value of the y co-ordinate for modulus of that x

So, for example the y co-ordinate at x=-1 is the same as the y co-ordinate at x=|-1|=1

does that help?
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#3
(Original post by clareeey)
with the function y =f(|x|) for any value of x, the y co-ordinate is the same as the value of the y co-ordinate for modulus of that x

So, for example the y co-ordinate at x=-1 is the same as the y co-ordinate at x=|-1|=1

does that help?
But the question doesn't give the cuve's equation so how can I find out what the y-coordinate at x=1 is?
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1 year ago
#4
(Original post by Rhys_M)
But the question doesn't give the cuve's equation so how can I find out what the y-coordinate at x=1 is?
Modules means 'the positive value of' so what does that mean about the parts of the graph below the x-axis?
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1 year ago
#5
(Original post by Rhys_M)
But the question doesn't give the cuve's equation so how can I find out what the y-coordinate at x=1 is?
You are giving the answer as a sketch

You have a graph of y=f(x), and you know that all the y values for -ve x are the same as +ve x values in the original function

which is enough information for a sketch
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#6
(Original post by clareeey)
You are giving the answer as a sketch

You have a graph of y=f(x), and you know that all the y values for -ve x are the same as +ve x values in the original function

which is enough information for a sketch
Ohhh -x has same y value as +x so you just disregard the (-1,3) and say we know (4,-2) so it must be (-4,-2) as its (|-4|,2).
Thank you so much.
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