Back
to top
Maths help
Watch this threadPage 1 of 1
Go to first unread
Skip to page:
Yazomi
Badges:
21
Rep:
?
You'll earn badges for being active around the site. Rep gems come when your posts are rated by other community members.
#1
dew1223345
Badges:
5
Rep:
?
You'll earn badges for being active around the site. Rep gems come when your posts are rated by other community members.
#2
Report
#2
don't combine differentiate both functions separately by dy/dt and dx/dt then divide the dy/dt by dx/dt to get dy/dx in the form of t
0
reply
davros
Badges:
16
Rep:
?
You'll earn badges for being active around the site. Rep gems come when your posts are rated by other community members.
#3
Report
#3
Firstly, you shouldn't be finding y in terms of x, you should be using the standard parametric formula dy/dx = (dy/dt) / (dx/dt).
Secondly you have created a problem for yourself - because t can take on negative values and y = 3sin t, it is possible for y to be negative. But when you write y = (something)^(1/2) you are choosing the positive value of the square root as that is the convention for both the square root symbol and the power 1/2 (otherwise you wouldn't have a valid function). Therefore you need to be really careful when manipulating parametric equations.
(Note: you could write x in terms of y^2 and use implicit differentiation if you have covered that. That would eliminate the problem caused by taking square roots.)
1
reply
X
Page 1 of 1
Go to first unread
Skip to page:
Quick Reply
