how much of the butanoic acid will be left over once it reacts with the NaOH (hint: you already have this calculation)
is it 0.165-9.25x10^-3 but also how would I know I need to think bout how much of the butanoic acid will be left over I think im struggling to understand buffers overall
is it 0.165-9.25x10^-3 but also how would I know I need to think bout how much of the butanoic acid will be left over I think im struggling to understand buffers overall
that calculation will give you the butanoic left over
from this reaction between the butanoic and naoh the butanoate anion is produced and that will act as a buffer in combination with the remaining butanoic acid