HNC engineering help

Hi, you forgot to take the arcsin of both sides while rearranging to make time t the subject. From the plot, the X refers to the first point in time when Vs = 3V

i understand this now thanks for that, the second part of the question asks me to make a graph like yours but im not sure if i am inputting it right into the software.

I'm doing HNC/D Mech Engineering. i was looking for help on this question i have answered but am sure is incorrect.

One of your commonly-used laboratory instantaneous test signal voltages (vs) is
described by the equation…

Vs = 6sin(2pift - (pi/4))

where f = 1MHz and t represents time.
Make time (t) the subject of this formula, and hence determine the first point in time when
the instantaneous signal voltage has a magnitude of +3V.

I've rearranged the formula thus t = sin(3/6)+(pi/4) / 2pi(1.10^6) = 2.013 x 10^-7

Any advise would be greatly appreciated.

i understand this now thanks for that, the second part of the question asks me to make a graph like yours but im not sure if i am inputting it right into the software.

What software are you using?

i have attached a screenshot of the software

Ive done the working outs but the figure im getting is 0.29 on the graph. When I worked it out I got 2.0833x10^-7 im confused shouldnt they be the same result.