graph of y=0^x

I understand why the graph looks the way it does for x= 1,2,3...., but when x=0 or -1 or -10, I don't understand why the graph looks like that. Please can someone explain this?
Also, 0^0 is 0 right? But my calc gives me a math error lol :/
also, why is 0^0 not 1?

Thank youuu xx

For 0^(-1) it's the same as 1/0? Which is?

1/0 is undefined. An argument is made that its infinity but if you take the limit of 1/x as x->0 from both sides of the y axis, 1/x tends to infinity of x->0+ and tends to -infinity if x->0- and since these are not equal there is no limit/ it is undefined.

For 0^(-1) it's the same as 1/0? Which is?

1/0 is undefined. An argument is made that its infinity but if you take the limit of 1/x as x->0 from both sides of the y axis, 1/x tends to infinity of x->0+ and tends to -infinity if x->0- and since these are not equal there is no limit/ it is undefined.

i feel like this is a stupid question, but then why does it look like the 1/x graph or something which have asymptotes?

tyy xx
i have no idea what a limit is lol but i'll just remember that