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trig question!!!

how do I solve this to find the value
(edited 3 years ago)
Reply 1
Original post by wevegota2319
how do I solve this to find the value

youve pretty much got it

1) simplify the (1+ tanx)^2 = (1 - tanx)^2 and then they are equivalent
it works in this case but you would normally lose a solution

2) expand (1+tanx)(1+tanx) = (1 - tanx)(1 - tanx)
you get the same answer as 1) but this is normally better as you dont lose any solutions this way for other equations which are similar
OKAY IVE GOT THAT now thanks! and then how do I find the solution!!

Original post by Deckoles
youve pretty much got it

1) simplify the (1+ tanx)^2 = (1 - tanx)^2 and then they are equivalent
it works in this case but you would normally lose a solution

2) expand (1+tanx)(1+tanx) = (1 - tanx)(1 - tanx)
you get the same answer as 1) but this is normally better as you dont lose any solutions this way for other equations which are similar
Original post by wevegota2319
OKAY IVE GOT THAT now thanks! and then how do I find the solution!!

as in how do I find the angle?
Reply 4
Original post by wevegota2319
as in how do I find the angle?

use the tan^-1(x) function on the calculator wdym?
Original post by wevegota2319
how do I solve this to find the value


One solution will occur when 45 + @ = 45 - @, i.e. when @ = 0

But then we can exploit the fact that the tangent function repeats every 180 degrees to find the full set of solutions from:

45 + @ = 45 - @ + 180k, where k is any integer
Original post by Deckoles
use the tan^-1(x) function on the calculator wdym?

I know I sound dumb but basically my text book says the answer is 0 and 180 degrees so I don't understand what tan=-1 isn't a value
Reply 7
Original post by wevegota2319
I know I sound dumb but basically my text book says the answer is 0 and 180 degrees so I don't understand what tan=-1 isn't a value

you want values of tanx which equal 0

that is any integer value of 180 degrees

tan^-1 is a function not a value
why does tax = 0?

Original post by Deckoles
you want values of tanx which equal 0

that is any integer value of 180 degrees

tan^-1 is a function not a value
Reply 9
Original post by wevegota2319
why does tax = 0?


Original post by Deckoles
youve pretty much got it

1) simplify the (1+ tanx)^2 = (1 - tanx)^2 and then they are equivalent
it works in this case but you would normally lose a solution

2) expand (1+tanx)(1+tanx) = (1 - tanx)(1 - tanx)
you get the same answer as 1) but this is normally better as you dont lose any solutions this way for other equations which are similar

solve either 1) or 2) to get tanx = 0

either 1 + tanx = 1 - tanx in which case 2tanx=0 thus tanx = 0

or expanding 2) gives you the same
Original post by Deckoles
solve either 1) or 2) to get tanx = 0

either 1 + tanx = 1 - tanx in which case 2tanx=0 thus tanx = 0

or expanding 2) gives you the same

oh I see that makes sense now, thank so much for helping me!
Original post by Deckoles
youve pretty much got it

1) simplify the (1+ tanx)^2 = (1 - tanx)^2 and then they are equivalent
it works in this case but you would normally lose a solution

2) expand (1+tanx)(1+tanx) = (1 - tanx)(1 - tanx)
you get the same answer as 1) but this is normally better as you dont lose any solutions this way for other equations which are similar

Both of these options miss half the solutions. 90 degrees is a solution: tan(45 + 90) = tan(45 - 90).
See my post #6.
Original post by old_engineer
Both of these options miss half the solutions. 90 degrees is a solution: tan(45 + 90) = tan(45 - 90).
See my post #6.

nice thanks - im terrible at converting radians to degrees so must have missed it when checking
Original post by Deckoles
nice thanks - im terrible at converting radians to degrees so must have missed it when checking

It is nothing to do with converting radians to degrees, but is rather due to the fact that the tan(A + @) formula yields an undefined result when either A or @ is equal to 90 degrees. This masks the potential solution @ = 90 degrees. To obtain the solution @ = 90 degrees you have to use the approach I outlined in post #6.
Original post by old_engineer
It is nothing to do with converting radians to degrees, but is rather due to the fact that the tan(A + @) formula yields an undefined result when either A or @ is equal to 90 degrees. This masks the potential solution @ = 90 degrees. To obtain the solution @ = 90 degrees you have to use the approach I outlined in post #6.

never said you need to do the conversion

im just saying ive forgotten a lot of the degree values as im more used to the radian values.

i appreciate the approach you have outlined but that wasnt my point - my point was i didnt check properly if i had missed a solution because of the lack of familiarity with the units

hope that clears it up

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