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Sets

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Reply 1
The question is that how do i prove that there is an inclusion between these two prepositions
(A B) C,
A (B C)
Reply 2
So what i did is
(x A ^x∈B)vx∈C
(x∈A^x∈C)v(x∈C^x∈B) - distributed U over intersection
so (x∈AnC)v(x∈CnB)
Original post by Selekt1234
So what i did is
(x A ^x∈B)vx∈C
(x∈A^x∈C)v(x∈C^x∈B) - distributed U over intersection
so (x∈AnC)v(x∈CnB)



(AB)CA(BC)(A\cap B)\cup C\supseteq A\cap (B\cup C)

I don't know what method/terminology you're expected to use given what you've put, BUT since the first set contains the second set, I would start with the second set, and show that if x is in that, then it's in the first set.
Reply 4
the question is that if there is inclusion prove it logically, if two sets are the same prove it logically hence i did the via that method
Original post by Selekt1234
the question is that if there is inclusion prove it logically, if two sets are the same prove it logically hence i did the via that method


I don't know why "that method" follows from "prove it logically". It's not a variation I've come across, so can't help you.

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