I have no resources on this type of question or have seen anything about mixtures of different materials for specific heat capacity, does anyone have any advice for getting to an answer with this question?
First Substance: Water, 3.2kg, 83∘C, 4180Jkg-1C-1
Second Substance: Paraffin, 4.3kg, 18∘C, 2030Jkg-1C-1
Write separate equations for temperature change of water and paraffin, assuming final temperature of both is the same, and that heat transfer from water = heat transfer to paraffin. Solve as simultaneous equations.
Write separate equations for temperature change of water and paraffin, assuming final temperature of both is the same, and that heat transfer from water = heat transfer to paraffin. Solve as simultaneous equations.
Yes, for this I did two equations. I don't think I'm doing this right and I'm unsure how to set it up. The answers I am getting are not being accepted.
Yes, for this I did two equations. I don't think I'm doing this right and I'm unsure how to set it up. The answers I am getting are not being accepted.
Oh, don't worry anymore I found it out. Thank you so much for trying to help earlier. I ended up doing this which didn't need simultaneous equations.
let: m1 = mass of hotter substance m2 = mass of colder substance c1 = spec heat cap hotter substance c2 = spec heat cap colder substance Th = Temp of hot Tc = Temp of cold t = temp change
energy lost = energy gained m1c1(Th - t) = m2c2(t - Tc)
Yes, for this I did two equations. I don't think I'm doing this right and I'm unsure how to set it up. The answers I am getting are not being accepted.
It would be better if you could show us how you get 224. As this is an old thread, we would close this old thread soon. If you cannot post a reply before it is closed, you can always start a new thread and link to this thread.
It would be better if you could show us how you get 224. As this is an old thread, we would close this old thread soon. If you cannot post a reply before it is closed, you can always start a new thread and link to this thread.