# is anyone willing to help with some exam questions?

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Hi, i am really struggling with some maths questions. I dont wish to be ridiculed or mocked because i really am struggling and mocking me wont help matters.

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#3

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**izziw19**)then with the perfect square uhh lets say you have an equation like this:

ax^2 + bx + c

for it to be a perfect square half of b squared should be c

so one example would be:

x^2 + 6x + 9

(half of 6 is 3 and 3 squared is 9 which is in fact the third number and so its a perfect square)

i mean that's the easy way to explain it and i think you'll get a mark for proving it like that but if you want to get all technical then whatever values you have should satisfy b^2 = 4ac

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#4

Expand all the brackets and simplify (remember foil) and you will be left with a quadratic expression. You should be able to factorise this quadratic, (using ac method since the coefficient of x^2 is bigger than 1). The factorised form can be written as a square, hence showing it is a perfect square.

Alternatively, expand all brackets and simplify. Then factorise 9 from the x^2 and x terms, and complete the square. After simplifying the terms, you will note it to be in the form of 9(x+c)^2. Since 9 = 3^2. Think about what happens when two squares are multiplied together ( e.g. m^2 x n^2, can be writtern as m x m x n x n , or mn x mn, which simplifiers to mn ^2)

In terms on how to improve in such questions, revisit quadratic factorisation, expanding and simplifying brackets + algebraic proofs

Alternatively, expand all brackets and simplify. Then factorise 9 from the x^2 and x terms, and complete the square. After simplifying the terms, you will note it to be in the form of 9(x+c)^2. Since 9 = 3^2. Think about what happens when two squares are multiplied together ( e.g. m^2 x n^2, can be writtern as m x m x n x n , or mn x mn, which simplifiers to mn ^2)

In terms on how to improve in such questions, revisit quadratic factorisation, expanding and simplifying brackets + algebraic proofs

Last edited by IReallyDoNotKnow; 1 month ago

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#5

(Original post by

Hi, i am really struggling with some maths questions. I dont wish to be ridiculed or mocked because i really am struggling and mocking me wont help matters.

**izziw19**)Hi, i am really struggling with some maths questions. I dont wish to be ridiculed or mocked because i really am struggling and mocking me wont help matters.

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Thankyou so much for your help

(Original post by

As braindeadpog has said, you can approach this question by multiplying out all the brackets, grouping the resulting terms into a single quadratic and then showing that the quadratic has two identical factors. But there is another way. You could note that 3x + 5 = 3x + 2 + 3, meaning that the x(3x + 5) term can be rewritten as x(3x + 2) + 3x. The complete expression should then consist of three terms, all of which have the factor (3x + 2). This give you another way forward.

**old_engineer**)As braindeadpog has said, you can approach this question by multiplying out all the brackets, grouping the resulting terms into a single quadratic and then showing that the quadratic has two identical factors. But there is another way. You could note that 3x + 5 = 3x + 2 + 3, meaning that the x(3x + 5) term can be rewritten as x(3x + 2) + 3x. The complete expression should then consist of three terms, all of which have the factor (3x + 2). This give you another way forward.

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(Original post by

Expand all the brackets and simplify (remember foil) and you will be left with a quadratic expression. You should be able to factorise this quadratic, (using ac method since the coefficient of x^2 is bigger than 1). The factorised form can be written as a square, hence showing it is a perfect square.

Alternatively, expand all brackets and simplify. Then factorise 9 from the x^2 and x terms, and complete the square. After simplifying the terms, you will note it to be in the form of 9(x+c)^2. Since 9 = 3^2. Think about what happens when two squares are multiplied together ( e.g. m^2 x n^2, can be writtern as m x m x n x n , or mn x mn, which simplifiers to mn ^2)

In terms on how to improve in such questions, revisit quadratic factorisation, expanding and simplifying brackets + algebraic proofs

**IReallyDoNotKnow**)Expand all the brackets and simplify (remember foil) and you will be left with a quadratic expression. You should be able to factorise this quadratic, (using ac method since the coefficient of x^2 is bigger than 1). The factorised form can be written as a square, hence showing it is a perfect square.

Alternatively, expand all brackets and simplify. Then factorise 9 from the x^2 and x terms, and complete the square. After simplifying the terms, you will note it to be in the form of 9(x+c)^2. Since 9 = 3^2. Think about what happens when two squares are multiplied together ( e.g. m^2 x n^2, can be writtern as m x m x n x n , or mn x mn, which simplifiers to mn ^2)

In terms on how to improve in such questions, revisit quadratic factorisation, expanding and simplifying brackets + algebraic proofs

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(Original post by

work through the (2x+1)(3x+2) and then work through the x(3x+5) and then you'll be left with terms which you can collect and add together

then with the perfect square uhh lets say you have an equation like this:

ax^2 + bx + c

for it to be a perfect square half of b squared should be c

so one example would be:

x^2 + 6x + 9

(half of 6 is 3 and 3 squared is 9 which is in fact the third number and so its a perfect square)

i mean that's the easy way to explain it and i think you'll get a mark for proving it like that but if you want to get all technical then whatever values you have should satisfy b^2 = 4ac

**braindeadpog**)work through the (2x+1)(3x+2) and then work through the x(3x+5) and then you'll be left with terms which you can collect and add together

then with the perfect square uhh lets say you have an equation like this:

ax^2 + bx + c

for it to be a perfect square half of b squared should be c

so one example would be:

x^2 + 6x + 9

(half of 6 is 3 and 3 squared is 9 which is in fact the third number and so its a perfect square)

i mean that's the easy way to explain it and i think you'll get a mark for proving it like that but if you want to get all technical then whatever values you have should satisfy b^2 = 4ac

6x^2+7x+2

ax^2+bx+c

a=6

b=7

c=2

to be a perf square should be b^2=4ac

7^2=4x6x2

which equals 48 so would it be equal or not?

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(Original post by

What are yours? We cannot do questions for you as it's against the rules/

**Muttley79**)What are yours? We cannot do questions for you as it's against the rules/

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#12

(Original post by

i am not asking for ANSWERS. i am asking for help. smhhhh

**izziw19**)i am not asking for ANSWERS. i am asking for help. smhhhh

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#13

(Original post by

i got this way of doing it

6x^2+7x+2

ax^2+bx+c

a=6

b=7

c=2

to be a perf square should be b^2=4ac

7^2=4x6x2

which equals 48 so would it be equal or not?

**izziw19**)i got this way of doing it

6x^2+7x+2

ax^2+bx+c

a=6

b=7

c=2

to be a perf square should be b^2=4ac

7^2=4x6x2

which equals 48 so would it be equal or not?

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reply

Report

#14

Hey, I think this video might help. https://www.tiktok.com/@gcsemathstok...77589564605958

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