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Hi,
Please can I have some help with part c of this question?
For part a I got, T = u/g
For part b I got, H = u^2/2g
So far I have found 3H = 3u^2/2g and using SUVAT
S = 3u^2/2g
U = u
V = ?
A = g
T = ? X - trying to solve
And then I was using my answer for part a , T and going to add this to the value of T when falling?
Any help please as cant get past this point yet?
Please can I have some help with part c of this question?
For part a I got, T = u/g
For part b I got, H = u^2/2g
So far I have found 3H = 3u^2/2g and using SUVAT
S = 3u^2/2g
U = u
V = ?
A = g
T = ? X - trying to solve
And then I was using my answer for part a , T and going to add this to the value of T when falling?
Any help please as cant get past this point yet?
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#3
(Original post by M.Johnson2111)
Hi,
Please can I have some help with part c of this question?
For part a I got, T = u/g
For part b I got, H = u^2/2g
So far I have found 3H = 3u^2/2g and using SUVAT
S = 3u^2/2g
U = u
V = ?
A = g
T = ? X - trying to solve
And then I was using my answer for part a , T and going to add this to the value of T when falling?
Any help please as cant get past this point yet?
Hi,
Please can I have some help with part c of this question?
For part a I got, T = u/g
For part b I got, H = u^2/2g
So far I have found 3H = 3u^2/2g and using SUVAT
S = 3u^2/2g
U = u
V = ?
A = g
T = ? X - trying to solve
And then I was using my answer for part a , T and going to add this to the value of T when falling?
Any help please as cant get past this point yet?
Or think about the s-t relationship, how long does it take to fall double, quadruple the distance in terms of T? Why 3H, how far from the peak is that?
Last edited by mqb2766; 1 month ago
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#5
Last edited by mqb2766; 1 month ago
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How would I do this rejecting the SUVAT approach?
So to sketch this would I let ut = x or t = x? from my equation
If I let ut = x, there is a repeated root of x = 9.8
Would this be my final answer, t = 9.8? I dont quite understand how thatd make sense but by substitution I think mathematically accepted?
So to sketch this would I let ut = x or t = x? from my equation
If I let ut = x, there is a repeated root of x = 9.8
Would this be my final answer, t = 9.8? I dont quite understand how thatd make sense but by substitution I think mathematically accepted?
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#7
a) and b) strongly suggest splitting up the trajectory into time to peak, peak to floor. What are the displacements and times "travelled" during those times. Remember displacement is a quadratic function of time.
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Okay so a graph for time to peak and one for time to floor?
S when peaking is 885
Then S from peak to floor = -885?
S when peaking is 885
Then S from peak to floor = -885?
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#9
(Original post by M.Johnson2111)
Okay so a graph for time to peak and one for time to floor?
S when peaking is 885
Then S from peak to floor = -885?
Okay so a graph for time to peak and one for time to floor?
S when peaking is 885
Then S from peak to floor = -885?
Last edited by mqb2766; 1 month ago
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#11
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Right so on the y-axis, I have H which is the displacement and then time on the x-axis
Where does the quadratic, equation involving T come into this and do I use this?
Where does the quadratic, equation involving T come into this and do I use this?
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#14
(Original post by M.Johnson2111)
Is this for 3c?
Is this for 3c?
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#15
(Original post by M.Johnson2111)
Right so on the y-axis, I have H which is the displacement and then time on the x-axis
Where does the quadratic, equation involving T come into this and do I use this?
Right so on the y-axis, I have H which is the displacement and then time on the x-axis
Where does the quadratic, equation involving T come into this and do I use this?
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Ive literally just got my axis labelled, trying to find the H and T values to be able to sketch
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#19
(Original post by M.Johnson2111)
S = ut + 1/2at^2
S = ut + 1/2at^2
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#20
(Original post by M.Johnson2111)
Ive literally just got my axis labelled, trying to find the H and T values to be able to sketch
Ive literally just got my axis labelled, trying to find the H and T values to be able to sketch
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