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Variable acceleration help please :)
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Hi, would anyone mind helping me with this question?
Here it is: https://hosting.photobucket.com/imag...t_20.46.52.png
Here's what I've done:
a) v = 4t - t^2
0 = 4t - t^2
t = 4
integrate v to get s: s = 2t^2 - 1/3t^3 + c
c = 0
t = 4 : s = 10.7m
b) Not sure what to do for this; I've sketched a v-t graph but the roots are at 4 and 0. Can I find the area under the curve using integration and then do the same for the section between 4 and 5, then add the areas together?
Here it is: https://hosting.photobucket.com/imag...t_20.46.52.png
Here's what I've done:
a) v = 4t - t^2
0 = 4t - t^2
t = 4
integrate v to get s: s = 2t^2 - 1/3t^3 + c
c = 0
t = 4 : s = 10.7m
b) Not sure what to do for this; I've sketched a v-t graph but the roots are at 4 and 0. Can I find the area under the curve using integration and then do the same for the section between 4 and 5, then add the areas together?
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(Original post by NaBrO)
b) Not sure what to do for this; I've sketched a v-t graph but the roots are at 4 and 0. Can I find the area under the curve using integration and then do the same for the section between 4 and 5, then add the areas together?
b) Not sure what to do for this; I've sketched a v-t graph but the roots are at 4 and 0. Can I find the area under the curve using integration and then do the same for the section between 4 and 5, then add the areas together?
https://hosting.photobucket.com/imag...-04_210723.jpg
I've got a negative area though.
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#3
You've got the distance from 0-4 from part a).
You make errors doing the same calculation in b).
On the return, integrate from 4 to 5 then flip the sign.
You make errors doing the same calculation in b).
On the return, integrate from 4 to 5 then flip the sign.
Last edited by mqb2766; 1 month ago
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#4
(Original post by NaBrO)
This is what I've done for (b):
https://hosting.photobucket.com/imag...-04_210723.jpg
I've got a negative area though.
This is what I've done for (b):
https://hosting.photobucket.com/imag...-04_210723.jpg
I've got a negative area though.
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(Original post by mqb2766)
You've got the distance from 0-4 from part a).
You make errors doing the same calculation in b).
On the return, integrate from 4 to 5 then flip the sign.
You've got the distance from 0-4 from part a).
You make errors doing the same calculation in b).
On the return, integrate from 4 to 5 then flip the sign.
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#6
(Original post by NaBrO)
May I ask where my errors are?
May I ask where my errors are?
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(Original post by mqb2766)
Yeah, you did it in part a) ...
Yeah, you did it in part a) ...
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